Thank you Skip, worked great. And thank you Tim for Tidying things up!
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On 2013-05-16 14:08, Skip Montanaro wrote:
> > So rather than
> >>a
> >>b
> >>c
> >>d
> >>e
> >>f
> > I would get [a, b, c, d, e, f]
>
> all_items = []
> for row in reader:
> all_items.append(row[0])
And following up here, this could be tidily rewritten as
all_items = [row[0] for row in re
On 2013-05-16 14:07, Skip Montanaro wrote:
> > len(reader) gives me an error.
>
> Apologies. len(list(reader)) should work. Of course, you'll wind
> up loading the entire CSV file into memory. You might want to just
> count row-by-row:
>
> n = 0
> for row in reader:
> n += 1
which can nic
> So rather than
>>a
>>b
>>c
>>d
>>e
>>f
> I would get [a, b, c, d, e, f]
all_items = []
for row in reader:
all_items.append(row[0])
Skip
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> len(reader) gives me an error.
Apologies. len(list(reader)) should work. Of course, you'll wind up
loading the entire CSV file into memory. You might want to just count
row-by-row:
n = 0
for row in reader:
n += 1
Skip
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I guess another way to accomplish this would be, is there any way that I can
turn the returned value for (column) into 1 list?
So rather than
>a
>b
>c
>d
>e
>f
I would get [a, b, c, d, e, f]
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On Thursday, May 16, 2013 2:40:08 PM UTC-4, Skip Montanaro wrote:
> Perhaps you want len(reader) instead? Or a counter which increments for
> every row read which has an item in column A?
>
>
>
> Skip
len(reader) gives me an error.
I tried a counter, but unfortunately due to the simplicity
Perhaps you want len(reader) instead? Or a counter which increments for
every row read which has an item in column A?
Skip
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I'm using the csv module to get information from a csv file. I have items
listed in Column A. I want to know how many items are listed in Column A.
import csv
with open('test.csv', 'r') as f:
reader = csv.reader(f)
for column in reader:
column = (column[0])
print(column)
