On Aug 12, 12:53 pm, Bernard bernard.ch...@gmail.com wrote:
On 12 août, 06:15, Martin mdeka...@gmail.com wrote:
Hi,
I have a string (see below) and ideally I would like to pull out the
decimal number which follows the bounding coordinate information. For
example ideal from this string
On Wed, 12 Aug 2009 05:12:22 -0700, Martin wrote:
I tried
re.findall((\w+COORDINATE).*\s+VALUE\s+=\s([\d\.\w-]+),s)
You need to put quotes around strings.
In this case, because you're using regular expressions, you should use a
raw string:
On Aug 12, 1:23 pm, Steven D'Aprano st...@remove-this-
cybersource.com.au wrote:
On Wed, 12 Aug 2009 05:12:22 -0700, Martin wrote:
I tried
re.findall((\w+COORDINATE).*\s+VALUE\s+=\s([\d\.\w-]+),s)
You need to put quotes around strings.
In this case, because you're using regular
On Aug 12, 1:42 pm, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:23 pm, Steven D'Aprano st...@remove-this-
cybersource.com.au wrote:
On Wed, 12 Aug 2009 05:12:22 -0700, Martin wrote:
I tried
re.findall((\w+COORDINATE).*\s+VALUE\s+=\s([\d\.\w-]+),s)
You need to put quotes around
On 12 août, 12:43, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:42 pm, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:23 pm, Steven D'Aprano st...@remove-this-
cybersource.com.au wrote:
On Wed, 12 Aug 2009 05:12:22 -0700, Martin wrote:
I tried
Bernard wrote:
On 12 août, 12:43, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:42 pm, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:23 pm, Steven D'Aprano st...@remove-this-
cybersource.com.au wrote:
On Wed, 12 Aug 2009 05:12:22 -0700, Martin wrote:
I tried
On Aug 12, 10:29 pm, Mark Lawrence breamore...@yahoo.co.uk wrote:
Bernard wrote:
On 12 août, 12:43, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:42 pm, Martin mdeka...@gmail.com wrote:
On Aug 12, 1:23 pm, Steven D'Aprano st...@remove-this-
cybersource.com.au wrote:
On Wed, 12 Aug 2009
