Gregory Ewing writes:
> A reasonably elegant way to fix this is to use list comprehensions
> for all except the innermost list:
>
>ff = [[0.0]*5 for i in xrange(5)]
Yes, this is a good approach. I should have suggested something like
this as a solution myself, rather than merely explaining
Mark Wooding wrote:
What [x] * n does is make a list, whose length is n, and all of whose
entries are precisely the value x. If x itself is a list, then you get
an outer list all of whose entries are the /same/ inner list
A reasonably elegant way to fix this is to use list comprehensions
for
g...@accutrol.com writes:
> What am I missing? I am using Python 3.1.2.
>
> ff = [[0.0]*5]*5
> ff#(lists 5x5 array of 0.0)
> for i in range(5):
> for j in range(3):
> ff[i][j] = i*10+j
> print (i,j,ff[i][j]) # correctly prints ff array values
>
> ff
g...@accutrol.com writes:
> What am I missing?
You're missing the fact that Python doesn't have a built-in “array”
type, nor really “subscripts” for them.
> ff = [[0.0]*5]*5
This creates a float object, ‘0.0’. It then creates a list containing
five references to that same object. It then create
On 11/8/10 3:56 PM, g...@accutrol.com wrote:
What am I missing? I am using Python 3.1.2.
ff = [[0.0]*5]*5
http://docs.python.org/faq/programming.html#how-do-i-create-a-multidimensional-list
--
Robert Kern
"I have come to believe that the whole world is an enigma, a harmless enigma
that is
