Re: yet another list comprehension question

2009-05-05 Thread Ricardo Aráoz
namekuseijin wrote: On May 4, 9:15 am, David Robinow drobi...@gmail.com wrote: On Mon, May 4, 2009 at 2:33 AM, namekuseijin namekuseijin.nos...@gmail.com wrote: ls = [(1,2), (3,4), (5, None), (6,7), (8, None)] [(x,y) for (x,y) in ls if y] [(1, 2), (3, 4), (6, 7)]

Re: yet another list comprehension question

2009-05-05 Thread namekuseijin
2009/5/5 Ricardo Aráoz ricar...@gmail.com: This seems to work for any length tuples : a = [(1,2), (3,4, 'goes'), (5,None), (6,7, 8, 'as', None), (8, None), (9, 0)] [tup for tup in a if not [e for e in tup if e == None]] [(1, 2), (3, 4, 'goes'), (9, 0)] Why that extra for? KISS a =

Re: yet another list comprehension question

2009-05-04 Thread namekuseijin
ls = [(1,2), (3,4), (5, None), (6,7), (8, None)] [(x,y) for (x,y) in ls if y] [(1, 2), (3, 4), (6, 7)] -- http://mail.python.org/mailman/listinfo/python-list

Re: yet another list comprehension question

2009-05-04 Thread Arnaud Delobelle
Snorri H a.a.ovtchinni...@gmail.com writes: On May 3, 6:13 am, Ross ross.j...@gmail.com wrote: I'm trying to set up a simple filter using a list comprehension. If I have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)] and I wanted to filter out all tuples containing None, I

Re: yet another list comprehension question

2009-05-04 Thread Snorri H
On May 3, 6:13 am, Ross ross.j...@gmail.com wrote: I'm trying to set up a simple filter using a list comprehension. If I have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)] and I wanted to filter out all tuples containing None, I would like to get the new list b = [(1,2),

Re: yet another list comprehension question

2009-05-04 Thread David Robinow
On Mon, May 4, 2009 at 2:33 AM, namekuseijin namekuseijin.nos...@gmail.com wrote: ls = [(1,2), (3,4), (5, None), (6,7), (8, None)] [(x,y) for (x,y) in ls if y] [(1, 2), (3, 4), (6, 7)] Nope. That filters out 0 as well as None. Not what the OP asked for. --

Re: yet another list comprehension question

2009-05-04 Thread namekuseijin
On May 4, 9:15 am, David Robinow drobi...@gmail.com wrote: On Mon, May 4, 2009 at 2:33 AM, namekuseijin namekuseijin.nos...@gmail.com wrote: ls = [(1,2), (3,4), (5, None), (6,7), (8, None)] [(x,y) for (x,y) in ls if y] [(1, 2), (3, 4), (6, 7)] Nope. That filters out 0 as well as None.

Re: yet another list comprehension question

2009-05-03 Thread ma
This isn't list comprehension, but it's something to keep in mind: b = filter(lambda x: None not in x, input_list) On Sat, May 2, 2009 at 10:25 PM, CTO debat...@gmail.com wrote: On May 2, 10:13 pm, Ross ross.j...@gmail.com wrote: I'm trying to set up a simple filter using a list

Re: yet another list comprehension question

2009-05-02 Thread Chris Rebert
On Sat, May 2, 2009 at 7:13 PM, Ross ross.j...@gmail.com wrote: I'm trying to set up a simple filter using a list comprehension. If I have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)] and I wanted to filter out all tuples containing None, I would like to get the new list b

Re: yet another list comprehension question

2009-05-02 Thread Ross
On May 2, 7:21 pm, Chris Rebert c...@rebertia.com wrote: On Sat, May 2, 2009 at 7:13 PM, Ross ross.j...@gmail.com wrote: I'm trying to set up a simple filter using a list comprehension. If I have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)] and I wanted to filter out all

Re: yet another list comprehension question

2009-05-02 Thread CTO
On May 2, 10:13 pm, Ross ross.j...@gmail.com wrote: I'm trying to set up a simple filter using a list comprehension. If I have a list of tuples, a = [(1,2), (3,4), (5,None), (6,7), (8, None)] and I wanted to filter out all tuples containing None, I would like to get the new list b = [(1,2),