To check a complete python expression use:
def check_open_close(expr):
try:
eval(expr)
except SyntaxError:
return False
else:
return True
This also ignores brackets in quotes, and checks = = operators are
syntatically correct etc...
But is may have side effects... ;-)
eg.
On May 2, 11:13 am, George Sakkis [EMAIL PROTECTED] wrote:
[1]http://en.wikipedia.org/wiki/Context-free_language
[2]http://en.wikipedia.org/wiki/Regular_language
[3]http://wiki.python.org/moin/LanguageParsing
Thanx for the link to these parsers. ANTLR looks interesting.
Yoyo:
On Fri, May 02, 2008 at 03:51:16PM -0700, NevilleDNZ wrote:
Thanx for the link to these parsers. ANTLR looks interesting.
Yoyo: http://www-users.cs.york.ac.uk/~fisher/software/yoyovwg/readme
I figured out a way to do it in python.
[...]
def check_open_close(str):
try:
Below is a (flawed) one line RegEx that checks curly brackets (from
awk/c/python input) are being matched. Is there a one liner for doing
this in python?
ThanX
N
re_open_close=(((\{))[^{}]*((?(0)\})))+
re_open_close=re.compile(re_open_close)
tests=
{ this is a test BAD
{ this is a test }
On May 2, 9:44 am, NevilleDNZ [EMAIL PROTECTED] wrote:
Below is a (flawed) one line RegEx that checks curly brackets (from
awk/c/python input) are being matched. Is there a one liner for doing
this in python?
ThanX
N
re_open_close=(((\{))[^{}]*((?(0)\})))+
On May 1, 7:44 pm, NevilleDNZ [EMAIL PROTECTED] wrote:
Below is a (flawed) one line RegEx that checks curly brackets (from
awk/c/python input) are being matched. Is there a one liner for doing
this in python?
There is not even a 1000-liner regular expression for this; it's a
context-free
