I've got a bunch of strings in a list:
vector = []
vector.append (foo)
vector.append (bar)
vector.append (baz)
I want to send all of them out a socket in a single send() call, so
they end up in a single packet (assuming the MTU is large enough). I
can do:
mySocket.send (.join (vector))
but
Roy Smith wrote:
I've got a bunch of strings in a list:
vector = []
vector.append (foo)
vector.append (bar)
vector.append (baz)
I want to send all of them out a socket in a single send() call, so
they end up in a single packet (assuming the MTU is large enough). I
can do:
On Sat, 01 Apr 2006 14:56:02 -0500, Roy Smith wrote:
I've got a bunch of strings in a list:
vector = []
vector.append (foo)
vector.append (bar)
vector.append (baz)
I want to send all of them out a socket in a single send() call, so
they end up in a single packet (assuming the MTU is
Peter Hansen [EMAIL PROTECTED] wrote:
B. Don't bother trying, because even if the MTU is large enough there is
absolutely no guarantee that the packet will stay intact all the way
through the network anyway (even if you use sendall() instead of send()).
This is true, but I'm generating the
In article [EMAIL PROTECTED],
Anthony Greene [EMAIL PROTECTED] wrote:
On Sat, 01 Apr 2006 14:56:02 -0500, Roy Smith wrote:
I've got a bunch of strings in a list:
vector = []
vector.append (foo)
vector.append (bar)
vector.append (baz)
I want to send all of them out a socket
Roy Smith [EMAIL PROTECTED] writes:
This is true, but I'm generating the message being sent in very small
chunks (often as small as 4 bytes at a time), and typically need to flush a
packet out onto the network after a few dozen bytes. Maybe at most a few
hundred. I don't know of any
On 1 Apr 2006 14:56:02 -0500, Roy Smith [EMAIL PROTECTED] wrote:
I've got a bunch of strings in a list:
vector = []
vector.append (foo)
vector.append (bar)
vector.append (baz)
I want to send all of them out a socket in a single send() call, so
they end up in a single packet (assuming the MTU is
