On Dec 12, 7:25 am, Lee Capps [EMAIL PROTECTED] wrote:
Regular expressions might be a good way to handle this.
import re
s = '[16, 16, 2, 16, 2, 16, 8, 16]'
get_numbers = re.compile('\d\d*').findall
numbers = [int(x) for x in get_numbers(s)]
Isn't '\d\d*' the same as '\d+' ?
And why
I still hold my vote that if you need to reverse the
stringification of a list, you shouldn't have stringified the list
and lost hold of the original list in the first place. That is the
solution above all others.
On Dec 12, 2007, at 10:26 AM, Paul McGuire wrote:
On Dec 12, 7:25 am, Lee
Another solution, possibly safer:
from cStringIO import StringIO
import csv
s = [16, 16, 2, 16, 2, 16, 8, 16]
sf = StringIO(s.strip()[1:-1])
list(csv.reader(sf))
[['16', ' 16', ' 2', ' 16', ' 2', ' 16', ' 8', ' 16']]
Bye,
bearophile
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On Wed, 12 Dec 2007 10:38:56 -0500, Calvin Spealman wrote:
I still hold my vote that if you need to reverse the stringification
of a list, you shouldn't have stringified the list and lost hold of the
original list in the first place. That is the solution above all others.
Naturally, but it
