> How can I get the *really* original command line that started my python
> interpreter?
>
> Werkzeug has a WSGI server which reloads itself when files are changed
> on disk. It uses `args = [sys.executable] + sys.argv` to kind of
> recreate the command line, and the uses subprocess.call to run that
> command line.
>
> BUT that's problematic as, when you run::
>
> python -m mypackage --config
>
> sys.argv printed in mypackage/__main__.py will be::
>
> ['/full/path/to/mypackage/__main__.py', '--config']
>
> so you get::
>
> python /full/path/to/mypackage/__main__.py --config
>
> instead of::
>
> python -m mypackage --config
>
>
> the difference in the 2 cases is what the current package is, and
> whether you can use relative imports.
BTW, the same thing happens in Python 3.2.2. To reproduce::
mkdir /tmp/X
cd /tmp/X
mkdir mypackage
touch mypackage/__init__.py mypackage/dummy.py
cat <<EOF > mypackage/__main__.py
from __future__ import print_function, absolute_import
import os, sys, subprocess
def rerun():
new_environ = os.environ.copy()
new_environ['TEST_CHILD'] = 'true'
args = [sys.executable] + sys.argv
subprocess.call(args, env=new_environ)
if os.environ.get('TEST_CHILD') != 'true':
Role = 'Parent'
rerun()
else:
Role = 'Child'
try:
from . import dummy
except:
print('Exception in %s' % Role)
else:
print('Success in %s' % Role)
EOF
Both::
python2 -m mypackage
or::
python3 -m mypackage
will print::
Exception in Child
Success in Parent
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