kowboy wrote:
I posted too quickly. A little performance testing told me that has_key
is somewhat slower than "in". I used a large number of string keys in
my test.
See my other post, but the reason has_key is slower is almost certainly
that it has to do a LOAD_ATTR:
$ python -m timeit -s "m = di
<[EMAIL PROTECTED]> wrote:
>I was wondering if the following two "if" statements compile down to
> the same bytecode for a standard Dictionary type:
>
> m = {"foo": 1, "blah": 2}
>
> if "foo" in m:
> print "sweet"
>
> if m.has_key("foo"):
> print "dude"
nope.
>>> import dis
>>> dis.dis(compile
[EMAIL PROTECTED] wrote:
I was wondering if the following two "if" statements compile down to
the same bytecode for a standard Dictionary type:
m = {"foo": 1, "blah": 2}
if "foo" in m:
print "sweet"
if m.has_key("foo"):
print "dude"
To answer the question you actually asked, you can use dis.dis
This is what I did
>>> import compiler
>>> exec1 = compiler.compile('''if "foo" in m: print "sweet"''', '',
'exec')
>>> exec2 = compiler.compile('''if m.has_key("foo"): print "dude"''',
'', 'exec')
>>> exec1.co_code
'd\x01\x00e\x00\x00j\x06\x00o\t\x00\x01d\x02\x00GHn\x01\x00\x01d\x00\x00S'
I posted too quickly. A little performance testing told me that has_key
is somewhat slower than "in". I used a large number of string keys in
my test.
--
http://mail.python.org/mailman/listinfo/python-list
I was wondering if the following two "if" statements compile down to
the same bytecode for a standard Dictionary type:
m = {"foo": 1, "blah": 2}
if "foo" in m:
print "sweet"
if m.has_key("foo"):
print "dude"
--
http://mail.python.org/mailman/listinfo/python-list
