I have a dict that I would like to print out in a series of columns,
rather than as a bunch of lines. Normally when you do print(dict), the
output will look something like this:
{'Header2': ['2', '5', '8'], 'Header3': ['3', '6', '9'], 'Header1':
['1', '4', '7'], 'Header4': ['10', '11', '12']}
I
On 6/14/2011 11:29 AM, Zachary Dziura wrote:
I have a dict that I would like to print out in a series of columns,
rather than as a bunch of lines. Normally when you do print(dict), the
output will look something like this:
{'Header2': ['2', '5', '8'], 'Header3': ['3', '6', '9'], 'Header1':
d={'Header2': ['2', '5', '8'], 'Header3': ['3', '6', '9'],
'Header1': ['1', '4', '7'], 'Header4': ['10', '11', '12']}
arr = []
for key,value in d.items():
line = ['{:10s}'.format(key)]
for num in value:
line.append('{:10s}'.format(num))
arr.append(line)
for
On 06/14/2011 05:29 PM, Zachary Dziura wrote:
I have a dict that I would like to print out in a series of columns,
rather than as a bunch of lines. Normally when you do print(dict), the
output will look something like this:
{'Header2': ['2', '5', '8'], 'Header3': ['3', '6', '9'], 'Header1':
On 14/06/2011 18:48, Zach Dziura wrote:
[snip]
I just have one quick question. On the line where you have zip(*arr),
what is the * for? Is it like the pointer operator, such as with C? Or
is it exactly the pointer operator?
[snip]
The * in the argument list of a function call unpacks the
Zachary Dziura zcdzi...@gmail.com writes:
What I want to know is how I can print out that information in a
column, where the header is the first line of the column, with the
data following underneath, like so:
I'm glad you got some good replies. It probably reflects badly on me
that my first
On Wed, Jun 15, 2011 at 9:40 AM, Ben Finney ben+pyt...@benfinney.id.au wrote:
Zachary Dziura zcdzi...@gmail.com writes:
What I want to know is how I can print out that information in a
column, where the header is the first line of the column, with the
data following underneath, like so:
I'm
On 6/14/2011 2:37 PM, MRAB wrote:
On 14/06/2011 18:48, Zach Dziura wrote:
[snip]
I just have one quick question. On the line where you have zip(*arr),
what is the * for? Is it like the pointer operator, such as with C? Or
is it exactly the pointer operator?
[snip]
The * in the argument list
