On 2005-10-04, Grant Edwards <[EMAIL PROTECTED]> wrote:
>> socket.error: (98, 'Address already in use')
>>
>> how can i get around that
>
> http://www.google.com/search?hl=en&q=socket.error%3A+%2898%2C+%27Address+already+in+use%27%29&btnG=Google+Search
>
> The first hit has this link which explain
On 2005-10-04, Mohammed Smadi <[EMAIL PROTECTED]> wrote:
> hi;
>
> i am executing program whcih uses a tcp socket. At the end of the program
> i do s.close() where s is my socket.
>
> when i try to run the program again right away i get the following error
> Traceback (most recent call last):
>
hi;
i am executing program whcih uses a tcp socket. At the end of the program
i do s.close() where s is my socket.
when i try to run the program again right away i get the following error
Traceback (most recent call last):
File "asterisk_login.py", line 14, in ?
s.bind(("", hp_port)) # do
