Sounds to me like the best solution is to simplify the implementation
and dispense with the list alternative. Why use a list if a dictionary
is suitable? Don't say performance: that's premature optimization.
Dictionaries already have what you need, apparently, with setdefault(),
so just use them
Ð ÐÑÐ, 27/02/2005 Ð 14:03 -0600, Bo Peng ÐÐÑÐÑ:
> To clearify the problem:
>
> The data is the count of something, for example a[90]=10. a may be a
> dictionary if the range is huge and a list when the range is reasonably
> small. In the dictionary case, I can use a.setdefault(80, 0) if key 80
Bo Peng wrote:
The data is the count of something, for example a[90]=10. a may be a
dictionary if the range is huge and a list when the range is reasonably
small. In the dictionary case, I can use a.setdefault(80, 0) if key 80
does not exist. In the list case, I have to check the length of list
To clearify the problem:
The data is the count of something, for example a[90]=10. a may be a
dictionary if the range is huge and a list when the range is reasonably
small. In the dictionary case, I can use a.setdefault(80, 0) if key 80
does not exist. In the list case, I have to check the lengt
Dear list,
My program needs to do calculation based on a giving data structure
(like a sparse matrix) with lots of missing values (invalid
indices/keys of lists/dictionaries).
The programing is difficult in that I have to use a try...except block
for every item access. I have written a functio
