determining fully qualified package class name

2007-10-11 Thread patrimith
Is there a comparable way to get the fully qualified name (package, module, and class name) in Python? Thanks, Patrick Smith -- View this message in context: http://www.nabble.com/determining-fully-qualified-package---class-name-tf4609111.html#a13161736 Sent from the Python - python-list mailing list archive

Re: determining fully qualified package class name

2007-10-11 Thread Marc 'BlackJack' Rintsch
On Thu, 11 Oct 2007 11:18:33 -0700, patrimith wrote: I am used to the following with Java: import some.package.MyClass; name = MyClass.class.getName(); The value for name will be some.package.MyClass. For Python, I find: from some.package.myclass import MyClass name =

Re: determining fully qualified package class name

2007-10-11 Thread Goldfish
import myPackage f = myPackage.foo() print f.__module__ + . + f.__class__.__name__ That should do it! -- http://mail.python.org/mailman/listinfo/python-list