Gordon Williams [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
I have to lists that I need to find the common numbers (2nd rounded to
nearest integral) and I am wondering if there is a more efficient way of
doing it.
a= [(123,1.3),(123,2.4),(123,7.8),(123,10.2)]
b= [(123,
Hi,
I have to lists that I need to find the common numbers (2nd rounded to
nearest integral) and I am wondering if there is a more efficient way of
doing it.
a= [(123,1.3),(123,2.4),(123,7.8),(123,10.2)]
b= [(123, 0.9), (123, 1.9), (123, 8.0)]
[ (i,round(j)) for i,j in a for l,m in b if
Gordon Williams wrote:
a= [(123,1.3),(123,2.4),(123,7.8),(123,10.2)]
b= [(123, 0.9), (123, 1.9), (123, 8.0)]
[ (i,round(j)) for i,j in a for l,m in b if (i,round(j)) ==
(l,round(m))]
d = {}
for (l, m) in b:
d[l, round(m)] = 1
result = []
for (i, j) in a:
t = (i, round(j))
if t in d:
On Thu, 2004-12-02 at 22:16, Greg Ewing wrote:
Gordon Williams wrote:
a= [(123,1.3),(123,2.4),(123,7.8),(123,10.2)]
b= [(123, 0.9), (123, 1.9), (123, 8.0)]
[ (i,round(j)) for i,j in a for l,m in b if (i,round(j)) ==
(l,round(m))]
d = {}
for (l, m) in b:
d[l, round(m)] = 1
result =
