TP wrote:
...
> def f():
def f_nested():
exec "a=2"
print a
f()
... What is the problem? Why?
What it wants is you to provide the "in context" portion of the
exec statement. I expect the reason it fails is that there is no
dictionary that is available as locals that encom
On Tue, 2009-01-13 at 16:13 +0100, TP wrote:
> Hi everybody,
>
> Try the following program:
>
>
> def f():
> def f_nested():
> exec "a=2"
> print a
> f()
>
>
> It yields an error.
> $ python nested_exec.py
> File "nested_exec.py", l
Hi everybody,
Try the following program:
def f():
def f_nested():
exec "a=2"
print a
f()
It yields an error.
$ python nested_exec.py
File "nested_exec.py", line 3
exec "a=2"
SyntaxError: unqualified exec is not allowed in functi
