Re: newbie: for loop within for loop question

The sets module is no longer needed, as we have the built-in sets type. Its even getting a literal syntax soon. As for the original problem, I agree on the homework smell. On Jun 15, 2008, at 9:31 PM, takayuki wrote: Dennis, thanks for your reply. unfortunately i accidentally posted only h

Re: newbie: for loop within for loop question

Dennis, thanks for your reply. unfortunately i accidentally posted only half of my question! the "real" post should be up now. my apologies. takayuki On Jun 16, 10:15 am, Dennis Lee Bieber <[EMAIL PROTECTED]> wrote: > On Sun, 15 Jun 2008 17:18:54 -0700 (PDT), takayuki > <[EMAIL PROTECTED]> d

newbie: for loop within for loop question

Hi everyone, I'm studying python via the excellent "how to think like a python programmer" book by Allen Downey. Noob question follows... I have a txt file (animals.txt) which contains the following text each on a separate line: aardvark, bat, cat, dog, elephant, fish, giraffe, horse, inchworm,

Re: for loop question

Steven D'Aprano <[EMAIL PROTECTED]> writes: > >> >>> pairs = (test[i:i+2] for i in xrange(len(test)-1)) > >> >>> for a,b in pairs: > >> ... print a,b > > > > for a, b in zip(test, test[1:]): > > print a, b > > May be unfortunately slow if test is half a gigabyte of data, what with > ess

Re: for loop question

On Oct 11, 4:40 am, Steven D'Aprano <[EMAIL PROTECTED] cybersource.com.au> wrote: > On Wed, 10 Oct 2007 20:25:00 +, Paul Hankin wrote: > >> A "works-for-me": > > >> >>> pairs = (test[i:i+2] for i in xrange(len(test)-1)) > >> >>> for a,b in pairs: > >> ... print a,b > > > for a, b in zip(

Re: for loop question

On Wed, 10 Oct 2007 20:25:00 +, Paul Hankin wrote: >> A "works-for-me": >> >> >>> pairs = (test[i:i+2] for i in xrange(len(test)-1)) >> >>> for a,b in pairs: >> ... print a,b > > for a, b in zip(test, test[1:]): > print a, b May be unfortunately slow if test is half a gigabyte of da

Re: for loop question

On 10/10/07, Carsten Haese <[EMAIL PROTECTED]> wrote: > > Instead of passing the file object directly to the csv parser, pass in a > generator that reads from the file and explicitly encodes the strings > into UTF-8, along these lines: > > def encode_to_utf8(f): > for line in f: > yield

Re: for loop question

On Wed, 2007-10-10 at 16:03 -0500, Robert Dailey wrote: > I've tried everything to make the original CSV module work. It just > doesn't. I've tried UTF-16 encoding What do you mean, "tried?" Don't you know what the file is encoded in? > (which works fine with codecs.open()) but when I pass in th

Re: for loop question

I've tried everything to make the original CSV module work. It just doesn't. I've tried UTF-16 encoding (which works fine with codecs.open()) but when I pass in the file object returned from codecs.open() into csv.reader(), the call to reader.next() fails because it says something isnt' in the rang

Re: for loop question

Tim Chase wrote: >> test = u"Hello World" >> >> for cur,next in test: >> print cur,next >> >> Ideally, this would output: >> >> 'H', 'e' >> 'e', 'l' >> 'l', 'l' >> 'l', 'o' >> etc... >> >> Of course, the for loop above isn't valid at all. I am just giving an >> example of what I'm trying to acc

Re: for loop question

On Oct 10, 4:12 pm, Tim Chase <[EMAIL PROTECTED]> wrote: > > test = u"Hello World" > > > for cur,next in test: > > print cur,next > > > Ideally, this would output: > > > 'H', 'e' > > 'e', 'l' > > 'l', 'l' > > 'l', 'o' > > etc... > > > Of course, the for loop above isn't valid at all. I am just

Re: for loop question

Paul Hankin wrote: > On Oct 10, 9:12 pm, Tim Chase <[EMAIL PROTECTED]> wrote: >> >>> pairs = (test[i:i+2] for i in xrange(len(test)-1)) >> >>> for a,b in pairs: >> ... print a,b > > for a, b in zip(test, test[1:]): > print a, b Very nice! I second this solution as better than my original

Re: for loop question

Very nice solution :) On 10/10/07, Paul Hankin <[EMAIL PROTECTED]> wrote: > > On Oct 10, 9:12 pm, Tim Chase <[EMAIL PROTECTED]> wrote: > > > test = u"Hello World" > > > > > for cur,next in test: > > > print cur,next > > > > > Ideally, this would output: > > > > > 'H', 'e' > > > 'e', 'l' > > >

Re: for loop question

All the ideas presented here are workable. I definitely have a lot of solutions to choose from. Thanks everyone for your help. I wasn't sure if there was some sort of language feature to naturally do this, so I had to post on the mailing list to make sure. -- http://mail.python.org/mailman/listinf

Re: for loop question

On Oct 10, 9:12 pm, Tim Chase <[EMAIL PROTECTED]> wrote: > > test = u"Hello World" > > > for cur,next in test: > > print cur,next > > > Ideally, this would output: > > > 'H', 'e' > > 'e', 'l' > > 'l', 'l' > > 'l', 'o' > > etc... > > > Of course, the for loop above isn't valid at all. I am just

Re: for loop question

On Wed, 2007-10-10 at 14:56 -0500, Robert Dailey wrote: > Hi, > > I'm currently writing my own CSV parser since the built in one doesn't > support Unicode. Why do you think you need a CSV parser that supports unicode? -- Carsten Haese http://informixdb.sourceforge.net -- http://mail.python.o

Re: for loop question

> test = u"Hello World" > > for cur,next in test: > print cur,next > > Ideally, this would output: > > 'H', 'e' > 'e', 'l' > 'l', 'l' > 'l', 'o' > etc... > > Of course, the for loop above isn't valid at all. I am just giving an > example of what I'm trying to accomplish. Anyone know how I c

Re: for loop question

Try this: test = u"Hello World" n = range(len(test)) for i in n: cur = test[i] try: next = test[i+1] except: next = "" print cur, next just On 10/10/07, Robert Dailey <[EMAIL PROTECTED]> wrote: > > Hi, > > I'm currently writing my own CSV parser since the built in on

for loop question

Hi, I'm currently writing my own CSV parser since the built in one doesn't support Unicode. I'm wondering if there's a way to iterate over the characters in a unicode string and have access to both the 'current' and the 'next' characters each iteration. For example: test = u"Hello World" for cur

Re: for loop question

for a in range(2, len(foo)): print a or maybe you need for a in range(1, len(foo)): print a ? York bruce wrote: > hi.. > > basic foor/loop question.. > > i can do: > > for a in foo > print a > > if i want to do something like > for a, 2, foo > print foo > > where go from 2, to foo

Re: for loop question

> Except that in the OP's example foo was a sequence, not an > integer. I think. Yes, possibly. But then, what's "from 2 to foo"? this way it might be for a in [2] + foo: print a -- http://mail.python.org/mailman/listinfo/python-list

Re: for loop question

On 2006-07-06, Daniel Haus <[EMAIL PROTECTED]> wrote: >> i can do: >> >> for a in foo >> print a >> >> if i want to do something like >> for a, 2, foo >> print foo >> >> where go from 2, to foo.. > just do: > > for a in range(2, foo+1): > print a Except that in the OP's example foo

RE: for loop question

'ppreaciate the answers duh... -bruce -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] Behalf Of Daniel Haus Sent: Thursday, July 06, 2006 2:02 PM To: [email protected] Subject: Re: for loop question just do: for a in range(2, foo+1): print a

Re: for loop question

just do: for a in range(2, foo+1): print a range(a, b) gives [a, a+1, a+2, ..., b-2, b-1] bruce schrieb: > hi.. > > basic foor/loop question.. > > i can do: > > for a in foo > print a > > if i want to do something like > for a, 2, foo > print foo > > where go from 2, to foo.. > >

Re: for loop question

On 7/6/06, bruce <[EMAIL PROTECTED]> wrote: hi..basic foor/loop question..i can do: for a in foo  print aif i want to do something like  for a, 2, fooprint foowhere go from 2, to foo..i can't figure out how to accomplish this... can someone point me to how/where this is demonstrated...You might

for loop question

hi.. basic foor/loop question.. i can do: for a in foo print a if i want to do something like for a, 2, foo print foo where go from 2, to foo.. i can't figure out how to accomplish this... can someone point me to how/where this is demonstrated... found plenty of google for for/loo