yes, i use the 2th way
<[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi
>
> The second style can be used:
>j = range(20)
> print j
> L = [x for x in j if x > 10]
> j = L
>
> There are another method such poping the item based on last index to 0:
> for i in range(len(j)-1,
yes. i understand now.
but i use another trick.
list is in vary size, so i do not wanna copy it.
"Jim" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> MaHahaXixi wrote:
> j = range(20)
> print j
> >
> > [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
> >
SORRY, my inattention
"Fredrik Lundh" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> "MaHahaXixi" <[EMAIL PROTECTED]> wrote:
>
> > for python, i am a newbie, but i did not found the warning of such usage
> > from the python tutorial
>
> "4.2 for Statements"
>
> "It is not saf
"MaHahaXixi" <[EMAIL PROTECTED]> wrote:
> for python, i am a newbie, but i did not found the warning of such usage
> from the python tutorial
"4.2 for Statements"
"It is not safe to modify the sequence being iterated over in the loop (this
can only happen for mutable sequence types,
yes. i think it does so.
it take me the whole afternoon to find out the bug (mine)
i change:
for i in range(len(j) -1, -1, -1):
d = j[i]
if d <= 10:
j.remove(d)
the real code is not so simple,so j[11:] will not work for me.
but, i think phthon could found that i remove the current e
Hi
The second style can be used:
j = range(20)
print j
L = [x for x in j if x > 10]
j = L
There are another method such poping the item based on last index to 0:
for i in range(len(j)-1,0-1,-1):
if j[i]<=10:
j.pop(i)
print j
Pujo
--
http://mail.python.org/mailman/listinf
MaHahaXixi wrote:
j = range(20)
print j
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
for k in j:
if k <= 10:
j.remove(k)
print j
[1, 3, 5, 7, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19]
Python 2.3.4 (#53, May 25 2004, 21:17:02) [MSC v.1200 32 bit (Intel)] on
win32
Type "co
Hi,
it is not python bug.
You refer the list j and remove the element in the same time, that is
the problem. Python dinamicaly goes to the next element with the same
index but apply it in the new list.
use this code instead:
j = range(20)
print j
L = [x for x in j if x > 10]
print L
Sinc
>>> j = range(20)
>>> print j
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
>>> for k in j:
if k <= 10:
j.remove(k)
>>> print j
[1, 3, 5, 7, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19]
>>>
Python 2.3.4 (#53, May 25 2004, 21:17:02) [MSC v.1200 32 bit (Intel)] on
win32
Type
