Marc 'BlackJack' Rintsch wrote:
> On Tue, 16 Oct 2007 06:18:51 +, Tim Roberts wrote:
>
> > John Machin <[EMAIL PROTECTED]> wrote:
> >>On Oct 15, 4:02 am, Abandoned <[EMAIL PROTECTED]> wrote:
> >>> Hi..
> >>> I have a list as a=[1, 2, 3 ] (4 million elements)
> >>> and
> >>> b=",".join(a)
On Tue, 16 Oct 2007 06:18:51 +, Tim Roberts wrote:
> John Machin <[EMAIL PROTECTED]> wrote:
>>On Oct 15, 4:02 am, Abandoned <[EMAIL PROTECTED]> wrote:
>>> Hi..
>>> I have a list as a=[1, 2, 3 ] (4 million elements)
>>> and
>>> b=",".join(a)
>>> than
>>> TypeError: sequence item 0: expecte
John Machin <[EMAIL PROTECTED]> wrote:
>On Oct 15, 4:02 am, Abandoned <[EMAIL PROTECTED]> wrote:
>> Hi..
>> I have a list as a=[1, 2, 3 ] (4 million elements)
>> and
>> b=",".join(a)
>> than
>> TypeError: sequence item 0: expected string, int found
>> I want to change list to a=['1','2','3']
Abandoned <[EMAIL PROTECTED]> wrote:
> Hi..
> I have a list as a=[1, 2, 3 ] (4 million elements)
> and
> b=",".join(a)
> than
> TypeError: sequence item 0: expected string, int found
> I want to change list to a=['1','2','3'] but i don't want to use FOR
> because my list very very big.
> I'm
On Oct 15, 4:02 am, Abandoned <[EMAIL PROTECTED]> wrote:
> Hi..
> I have a list as a=[1, 2, 3 ] (4 million elements)
> and
> b=",".join(a)
> than
> TypeError: sequence item 0: expected string, int found
> I want to change list to a=['1','2','3'] but i don't want to use FOR
> because my list v
1. Use a generator expression:
b = ",".join(str(i) for i in a)
or
2. Use imap
from itertools import imap
b = ",".join(imap(str, a))
--
http://mail.python.org/mailman/listinfo/python-list
Hi..
I have a list as a=[1, 2, 3 ] (4 million elements)
and
b=",".join(a)
than
TypeError: sequence item 0: expected string, int found
I want to change list to a=['1','2','3'] but i don't want to use FOR
because my list very very big.
I'm sorry my bad english.
King regards
--
http://mail.pyt
