On Thu, Jan 22, 2009 at 11:35 AM, blueiur wrote:
> i think it's best way
> lst = [0, 1, 3.14, 20, 8, 8, 3.14]
> len( filter(lambda x: x > 3.13 and x < 3.15, lst) )
> 2
I prefer this way (cleaner):
>>> lst = [0, 1, 3.14, 20, 8, 8, 3.14]
>>> len([x for x in lst if 3.13 < x < 3.15])
2
>>>
cheers
J
o use == in floating
> point operations.)
>
> Thank you
>
> culpritNr1
>
> --
> View this message in
> context:http://www.nabble.com/list-subsetting-tp21593123p21593123.html
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culpritNr1 wrote:
Thank you Fogelbird and Jeff.
I actually tried to find out if such function existed. I did
help("count")
no Python documentation found for 'count'
[snip]
'count' is a method of the list class, so you need:
help(list.count)
and if you want help on the list class then it's
On Jan 21, 5:22 pm, culpritNr1 wrote:
> Thank you Fogelbird and Jeff.
>
> I actually tried to find out if such function existed. I did
>
> >>> help("count")
>
> no Python documentation found for 'count'
>
> Anyway. More than counting, I am
culpritNr1 wrote:
Thank you Fogelbird and Jeff.
I actually tried to find out if such function existed. I did
help("count")
no Python documentation found for 'count'
Anyway. More than counting, I am interested in list subsetting in a simple
way. Forget about counting.
culpritNr1 writes:
> Anyway. More than counting, I am interested in list subsetting in a simple
> way. Forget about counting. Say I have a list of lists and I want to pull
> only the rows where the second "column" equals 3.14.
list_of_lists = [[1.414,2.718,3.14],[4.00,3.
Thank you Fogelbird and Jeff.
I actually tried to find out if such function existed. I did
>>> help("count")
no Python documentation found for 'count'
Anyway. More than counting, I am interested in list subsetting in a simple
way. Forget about counting. Say I have
I do not mean to use == in floating
> > point operations.)
> >
> > Thank you
> >
> > culpritNr1
> >
> > --
> > View this message in context:
> http://www.nabble.com/list-subsetting-tp21593123p21593123.html
> > Sent from the Python - pytho
culpritNr1 writes:
> a = [0 , 1, 3.14, 20, 8, 8, 3.14]
>
> Is there a simple python way to count the number of 3.14's in the list in
> one statement?
n = sum(1 for x in a if x == 3.14)
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culpritNr1 wrote in
news:mailman.7713.1232574803.3487.python-l...@python.org in
comp.lang.python:
>
> Hello All,
>
> Say I have a list like this:
>
> a = [0 , 1, 3.14, 20, 8, 8, 3.14]
>
> Is there a simple python way to count the number of 3.14's in the list
> in one statement?
>
> In R I do
FogleBird:
> a.count(3.14)
If the values to count are approximated FP values, then you may need
something more complex, like:
leniter(ifilter(somefunction, a))
Where somefunction uses an approximated comparison, and leniter is
just a function that counts the items of a generic iterator.
Bye,
be
1, 3.14, 20, 8, 8, 3.14)
>
> length( a[ a[]==3.14 ] )
>
> How do I do that in standard python?
>
> (Note that this is just an example, I do not mean to use == in floating
> point operations.)
>
> Thank you
>
> culpritNr1
>
> --
> View this message in
>
1, 3.14, 20, 8, 8, 3.14)
>
> length( a[ a[]==3.14 ] )
>
> How do I do that in standard python?
>
> (Note that this is just an example, I do not mean to use == in floating
> point operations.)
>
> Thank you
>
> culpritNr1
>
> --
> View this message in
>
(Note that this is just an example, I do not mean to use == in floating
point operations.)
Thank you
culpritNr1
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http://www.nabble.com/list-subsetting-tp21593123p21593123.html
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