If document order doesn't matter, try sorting the elements of each level in
the two documents by some arbitrary deterministic key, such as (tag name,
text, attr count, whatever), and then compare them in order, instead of trying
to find matches in multiple passes. itertools.groupby() might be
code_berzerker wrote:
If document order doesn't matter, try sorting the elements of each level in
the two documents by some arbitrary deterministic key, such as (tag name,
text, attr count, whatever), and then compare them in order, instead of
trying
to find matches in multiple passes.
Not in your code.
Stefan
Not sure what you mean, but I tested and so far every document with
the same order of elements had number of comparisons equal to number
of nodes.
--
http://mail.python.org/mailman/listinfo/python-list
code_berzerker wrote:
Not in your code.
Stefan
Not sure what you mean, but I tested and so far every document with
the same order of elements had number of comparisons equal to number
of nodes.
Sorry, missed the let2.remove(foundEl) line.
Stefan
--
off the top of my head (untested):
def equal(a, b):
... if a.tag != b.tag or a.attrib != b.attrib:
... return False
... if a.text != b.text or a.tail != b.tail:
... return False
... if len(a) != len(b):
... return False
... if any(not equal(a, b)
code_berzerker wrote:
Thanks for help. Thats inspiring, tho not exactly what I need, coz
ignoring document order is requirement (ignoring changes in order of
different siblings of the same type, etc). I plan to try something
like that:
def xmlCmp(xmlStr1, xmlStr2):
et1 =
I'd like to know if there is any built in mechanism in lxml that lets
you check equality of two nodes from separate documents. I'd like it
to ignore attribute order and so on. It would be even better if there
was built in method for checking equality of whole documents (ignoring
document order).
code_berzerker [EMAIL PROTECTED]:
I'd like to know if there is any built in mechanism in lxml that lets
you check equality of two nodes from separate documents. I'd like it
to ignore attribute order and so on. It would be even better if there
was built in method for checking equality of whole
On Jul 23, 6:29 pm, Stefan Behnel [EMAIL PROTECTED] wrote:
Your requirements for a single Element are simple enough to write it in three
to five lines of Python code (depending on your definition of equality).
Checking this equality recursively is another two to three lines. Not complex
code_berzerker wrote:
Your requirements for a single Element are simple enough to write it in three
to five lines of Python code (depending on your definition of equality).
Checking this equality recursively is another two to three lines. Not complex
enough to be considered a wheel in the first
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