You have three ways to do what you want :
First wayt is to use lambda. Then, you want to write :
>>> map(lambda x: re.sub("[a-z]", "", x), test)
Second is to use regular named function :
>>> def remove_letters( s ):
... re.sub("[a-z]", "", s)
>>> map(remove_letters, test)
A third way would be to
On Fri, 21 Jan 2005 12:37:46 +, Simon Brunning
<[EMAIL PROTECTED]> wrote:
> This what you want?
>
> >>> import re
> >>> test = ["a1", "a2", "a3"]
> >>> test = [re.sub("[a-z]", "", item) for item in test]
> >>> test
> ['1', '2', '3']
Or, if you *must* use map, you can do:
>>> test = map(lambd
On 21 Jan 2005 04:25:27 -0800, Stu <[EMAIL PROTECTED]> wrote:
> I have recently switched over to Python from Perl. I want to do
> something like this in Python:
>
> @test = ("a1", "a2", "a3");
> map {s/[a-z]//g} @test;
> print @test;
>
> However, I take it there is no equivalent to $_ in Python.
I have recently switched over to Python from Perl. I want to do
something like this in Python:
@test = ("a1", "a2", "a3");
map {s/[a-z]//g} @test;
print @test;
However, I take it there is no equivalent to $_ in Python. But in that
case how does map pass the elements of a sequence to a function? I
