On Dec 31 2009, 5:13 pm, davidj411 wrote:
> I am not sure why this behavior is this way.
> at beginning of script, i want to create a bunch of empty lists and
> use each one for its own purpose.
> however, updating one list seems to update the others.
>
> >>> a = b = c = []
> >>> a.append('1')
> >
On 1/1/2010 3:13 AM, davidj411 wrote:
I am not sure why this behavior is this way.
at beginning of script, i want to create a bunch of empty lists and
use each one for its own purpose.
however, updating one list seems to update the others.
a = b = c = []
a.append('1')
a.append('1')
a.append('1'
On Thu, 31 Dec 2009 11:32:04 -0500, Andreas Waldenburger
wrote:
On Thu, 31 Dec 2009 08:13:35 -0800 (PST) davidj411
wrote:
I am not sure why this behavior is this way.
at beginning of script, i want to create a bunch of empty lists and
use each one for its own purpose.
however, updating one l
On Thu, 31 Dec 2009 08:13:35 -0800 (PST) davidj411
wrote:
> I am not sure why this behavior is this way.
> at beginning of script, i want to create a bunch of empty lists and
> use each one for its own purpose.
> however, updating one list seems to update the others.
>
> >>> a = b = c = []
No, y
On Thu, Dec 31, 2009 at 11:13, davidj411 wrote:
> I am not sure why this behavior is this way.
> at beginning of script, i want to create a bunch of empty lists and
> use each one for its own purpose.
> however, updating one list seems to update the others.
>
a = b = c = []
a.append('1')
I am not sure why this behavior is this way.
at beginning of script, i want to create a bunch of empty lists and
use each one for its own purpose.
however, updating one list seems to update the others.
>>> a = b = c = []
>>> a.append('1')
>>> a.append('1')
>>> a.append('1')
>>> c
['1', '1', '1']
>
