alb wrote:
But wait, .join() only accepts strings so let's change
yield [node]
to
yield [node.name] # str(node) would also work
Again my question, why not simply yield node.name?
I've been conditioned to build a string from many substrings like so
parts = [foo, bar, baz]
text =
alb wrote:
def read_tree(rows, levelnames):
root = Node(#ROOT, #ROOT)
old_level = 0
stack = [root]
for i, row in enumerate(rows, 1):
I'm not quite sure I understand what is the stack for. As of now is a
list whose only element is root.
The stack is used to emulate
alb wrote:
def read_tree(rows, levelnames):
root = Node(#ROOT, #ROOT)
old_level = 0
stack = [root]
for i, row in enumerate(rows, 1):
I'm not quite sure I understand what is the stack for. As of now is a
list whose only element is root.
The stack is used to emulate
Hi Peter,
Peter Otten __pete...@web.de wrote:
[]
Let's start with the simplest:
Peter Otten __pete...@web.de wrote:
def show2(self):
yield str(self)
for child in self.children:
yield from child.show2()
[]
Given a tree
A -- A1
A2 -- A21
alb wrote:
Hi Peter, I'll try to comment the code below to verify if I understood
it correctly or missing some major parts. Comments are just below code
with the intent to let you read the code first and my understanding
afterwards.
Let's start with the simplest:
Peter Otten
Peter Otten wrote:
[A, A1, A21, A22]
Finally the append_nodes(A3, nodes) will append A3 and then return because
it has no children, and we end up with
nodes = [A, A1, A21, A22, A3]
Yay, proofreading! Both lists should contain A2:
[A, A1, A2, A21, A22]
nodes = [A, A1, A2, A21, A22, A3]
Hi Peter, I'll try to comment the code below to verify if I understood
it correctly or missing some major parts. Comments are just below code
with the intent to let you read the code first and my understanding
afterwards.
Peter Otten __pete...@web.de wrote:
[]
$ cat parse_column_tree.py
Hi Peter,
Peter Otten __pete...@web.de wrote:
[]
def show2(self):
yield str(self)
for child in self.children:
yield from child.show2()
here is what I get:
SyntaxError: invalid syntax
debian@debian:example$ python3 export_latex.py doctree.csv
File
On Thu, Jan 29, 2015 at 1:59 PM, Mark Lawrence breamore...@yahoo.co.uk wrote:
On 29/01/2015 21:32, alb wrote:
Hi MRAB,
MRAB pyt...@mrabarnett.plus.com wrote:
[]
SyntaxError: invalid syntax
debian@debian:example$ python3 export_latex.py doctree.csv
File export_latex.py, line 36
Hi MRAB,
MRAB pyt...@mrabarnett.plus.com wrote:
[]
SyntaxError: invalid syntax
debian@debian:example$ python3 export_latex.py doctree.csv
File export_latex.py, line 36
yield from child.show2()
^
SyntaxError: invalid syntax
and I've tried with both python and python3
Hi Tim,
Tim Chase python.l...@tim.thechases.com wrote:
[]
I know about the xlrd module to get data from excel
If I have to get my code to read Excel files, xlrd is usually my
first and only stop.
It provides quite a good interface to manipulating excel files and I
find it pretty easy
On 29/01/2015 21:32, alb wrote:
Hi MRAB,
MRAB pyt...@mrabarnett.plus.com wrote:
[]
SyntaxError: invalid syntax
debian@debian:example$ python3 export_latex.py doctree.csv
File export_latex.py, line 36
yield from child.show2()
^
SyntaxError: invalid syntax
and I've tried
On 2015-01-29 21:02, alb wrote:
Hi Peter,
Peter Otten __pete...@web.de wrote:
[]
def show2(self):
yield str(self)
for child in self.children:
yield from child.show2()
here is what I get:
SyntaxError: invalid syntax
debian@debian:example$ python3 export_latex.py
On Fri, Jan 30, 2015 at 8:32 AM, alb al.bas...@gmail.com wrote:
Ok, that either means I need to upgrade to 3.3 or need to modify the
snippet to a suitable syntax that would work with other versions.
You could replace yield from child.show2() with:
for val in child.show2(): yield val
and it
On 2015-01-28 10:12, alb wrote:
I've a document structure which is extremely simple and represented
on a spreadsheet in the following way (a made up example):
subsystem | chapter | section | subsection | subsubsec |
A | | || |
| func0
alb wrote:
Hi everyone,
I've a document structure which is extremely simple and represented on a
spreadsheet in the following way (a made up example):
subsystem | chapter | section | subsection | subsubsec |
A | | || |
| func0 |
Hi Peter,
Peter Otten __pete...@web.de wrote:
[]
You can save the excel sheet as csv so that you an use the csv module which
may be easier to use than xlrd. The rest should be doable by hand. Here's
what I hacked together:
$ cat parse_column_tree.py
import csv
def column_index(row):
Hi everyone,
I've a document structure which is extremely simple and represented on a
spreadsheet in the following way (a made up example):
subsystem | chapter | section | subsection | subsubsec |
A | | || |
| func0 | |
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