hanumizzle wrote:
(snip)
Regexes are usually passed as literals directly to re.compile().
For which definition of usually ?
--
bruno desthuilliers
python -c print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])
--
On 10/9/06, Bruno Desthuilliers [EMAIL PROTECTED] wrote:
hanumizzle wrote:
(snip)
Regexes are usually passed as literals directly to re.compile().
For which definition of usually ?
From definition of personal experience: all of the code I've written
or seen that used small regexes in such a
On Oct 6, 11:33 pm, hanumizzle [EMAIL PROTECTED] wrote:
import re
snip
if line.startswith('instr'):
p = re.compile(r'(\d+)\s+;(.*)$')
m = p.search(line)
return (m.group(1), m.group(2))
You probably don't want startswith, in case there are initial spaces in
the line. Also, since the
I was trying something like this
digits = re.compile(\d)
if digits in line
instr_number = digits.search(line)
because it looked realy cool when I saw it in a recent post... and then
the same thing
for just (';') didn't seem to return anything except one line and some
hex that came
On 6 Oct 2006 23:09:08 -0700, MonkeeSage [EMAIL PROTECTED] wrote:
On Oct 6, 11:33 pm, hanumizzle [EMAIL PROTECTED] wrote:
import re
snip
if line.startswith('instr'):
p = re.compile(r'(\d+)\s+;(.*)$')
m = p.search(line)
return (m.group(1), m.group(2))
You probably don't
I think I am very close the return line is tripping me up. (this is
the first list that I have tried to program in python)
return (s.group[1], s.group[2])
Traceback (most recent call last):
File C:\Python24\Lib\site-packages\boa-constructor\test of
snake\test_of_csoundroutines_list.py, line
I am not sure if I am having trouble with the test program or the
routine.. (I had the brackets in the wrong place on the other)
IDLE 1.1.3 No Subprocess
['1', 'String pad']
I get this but I have at least three lines and the
v = []
v =
[EMAIL PROTECTED] wrote:
I think I am very close the return line is tripping me up. (this is
the first list that I have tried to program in python)
return (s.group[1], s.group[2])
Traceback (most recent call last):
File C:\Python24\Lib\site-packages\boa-constructor\test of
apologies if I annoy and for spacing (google)
def csdInstrumentList(from_file):
Returns a list of .csd instruments and any comment lines after the
instrument
infile = open(from_file, 'r')
temp_number = 0
for line in infile:
if 'instr' in line:
s = re.split(r'
p.s. this is the one I need to finish to release the csoundroutines
library
www.dexrow.com
[EMAIL PROTECTED] wrote:
apologies if I annoy and for spacing (google)
def csdInstrumentList(from_file):
Returns a list of .csd instruments and any comment lines after the
instrument
On 6 Oct 2006 21:07:43 -0700, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
I want comment returned in an array and instr_number returned in an
array.
Let me see if I understand what you want: if there is a line that
starts with instr (best tested with line.startswith('instr') :)), you
want the
Think you need a regex like this: regex =
r\s*instr\s+([0-9]+)\s*(;.*)?
Then:
import re
test = re.compile(regex)
testing is done as follows:
res = test.match(mystring)
if res:
number = res.group(1) # always a string consisting of decimals
comment = res.group(2) # string starting with ;
On 10/7/06, goyatlah goyatlah wrote:
Think you need a regex like this: regex =
r\s*instr\s+([0-9]+)\s*(;.*)?
[0-9] maybe written simply as \d (d for digit)
Then:
import re
test = re.compile(regex)
Regexes are usually passed as literals directly to re.compile().
testing is done as
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