Say I have a module with a function f in it, and I do
psyco.bind (f)
Is there any simple/easy/elegant way to retain a reference to the
*unoptimized* version of f so I can call them both and compare
performance?I've tried
f2 = copy.deepcopy (f)
psyco.bind (f)
but that doesn't work. Other
On Sun, 03 Feb 2008 10:06:04 -0800, miller.paul.w wrote:
Say I have a module with a function f in it, and I do
psyco.bind (f)
Is there any simple/easy/elegant way to retain a reference to the
*unoptimized* version of f so I can call them both and compare
performance?
What about
Thanks for your reply. It's been a while since I've used psyco, and
it seems either some functions have been added, or I've never needed
the other ones. :-)
For the record, it looks like
psyco.bind (f)
f2 = psyco.unproxy(f)
would leave me with an optimized f and a function f2 which is the
miller:
Is there any simple/easy/elegant way to retain a reference to the
*unoptimized* version of f so I can call them both and compare
performance?
A simple solution is to defer the optimization. That is test the
original code, call Psyco, then test it again:
def somefunc():
...
from
On Feb 3, 2:19 pm, [EMAIL PROTECTED] wrote:
simple solution is to defer the optimization. That is test the
original code, call Psyco, then test it again:
I had thought of that, but it didn't really meet my requirements. I
might want the unoptimized function back at some point after I call
the
