parameter, then the server return correct reply.
para = MyData(0.5,0.01)
server.Fun([para ], [ ] )
From:
dieter
To:
python-list@python.org
Date:
01/23/2015 03:26 PM
Subject:
Re: python client call Java server by xmlrpc
Sent by:
"Python-list"
fan.di...@kodak.com writes:
>
fan.di...@kodak.com writes:
> I have xmlrpc server written in Java, and it has a method like
>
> Fun( vector, vector), the vector is array of user-defined object, which is
> a class extends HashMap.
>
> And I call it like:
>
> server = xmlrpclib.ServerProxy("http://myserver";)
>
> server.Fun( [
Hi all
I have xmlrpc server written in Java, and it has a method like
Fun( vector, vector), the vector is array of user-defined object, which is
a class extends HashMap.
And I call it like:
server = xmlrpclib.ServerProxy("http://myserver";)
server.Fun( [ {"0.5":0.1}], [ ] )
It always fails
