thanks everybody.
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thanks all,
Yes. That's the exact purpose of the in-place operators when they deal with
mutable objects. What else did you expect?
well, frankly I expected a |= b to mean exactly the same as a = a | b
regardless of the object type.
The manual explicitly specifies that mutable objects may
akva wrote:
could you please refer me a link where this is specified? I couldn't
find it in python documentation
http://docs.python.org/ref/augassign.html
An augmented assignment expression like x += 1 can be rewritten as x =
x + 1 to achieve a similar, but not exactly equal effect. In the
Hi All,
what's the exact semantics of the |= operator in python?
It seems that a |= d is not always equivalent to a = a | d
For example let's consider the following code:
def foo(s):
s = s | set([10])
def bar(s):
s |= set([10])
s = set([1,2])
foo(s)
print s # prints set([1, 2])
bar(s
akva wrote:
Hi All,
what's the exact semantics of the |= operator in python?
It seems that a |= d is not always equivalent to a = a | d
For example let's consider the following code:
def foo(s):
s = s | set([10])
def bar(s):
s |= set([10])
s = set([1,2])
foo(s)
print
akva wrote:
Hi All,
what's the exact semantics of the |= operator in python?
It seems that a |= d is not always equivalent to a = a | d
The manual explicitly specifies that mutable objects may implement the
operation part of operation-assignments by updating in place -- so
