def sum1(*a): return(sum(i*i for i in a))
def sum2(a): return(sum(i*i for i in a))
a=[1,2,3]
print(sum1(*a), sum2(a))
showed above: the result from sum1() and sum2() is the same. So, what
is the difference between f(a) and f(*a)
--
On Tue, 02 Sep 2008 06:24:21 -0700, qxyuestc wrote:
showed above: the result from sum1() and sum2() is the same. So, what is
the difference between f(a) and f(*a)
f(a) - f([1, 2, 3])
f(*a) - f(1, 2, 3)
Ciao,
Marc 'BlackJack' Rintsch
--
[EMAIL PROTECTED] a écrit :
def sum1(*a): return(sum(i*i for i in a))
def sum2(a): return(sum(i*i for i in a))
a=[1,2,3]
print(sum1(*a), sum2(a))
showed above: the result from sum1() and sum2() is the same. So, what
is the difference between f(a) and f(*a)
