-- Forwarded message -
From: Arshad Zama
Date: Thu, Jan 3, 2019 at 10:27 PM
Subject: PROBLEM IN LAUNCHING PYTHON...
To:
HELLO SIR,
I'm facing some issue while launching the python ide on windows 8.1 pro.
Kindly help me!!...
--
https://mail.python.org/mailman/listinfo/python-lis
Tim Chase wrote:
> def all_equal(iterable):
> i = iter(iterable)
> first = next(i)
> return all(x == first for x in i)
>
> It's undefined for an empty list (well, it throws a StopIteration
> but you can special-case that), but should hand the cases with
> 1 element and 2+ elements (
Bob van der Poel wrote:
> I need to see if all the items in my list are the same. I was using set()
> for this, but that doesn't work if items are themselves lists. So,
> assuming that a is a list of some things, the best I've been able to come
> up with it:
>
> if a.count( targ ) == len(a):
Today, we’re happy to announce our pre-launch website under the
official EuroPython 2019 URL:
* https://ep2019.europython.eu/ *
Dates and Venues
EuroPython will be held from July 8-14 2019 in Basel, Switzerland, at
the Congress Center Basel (BCC) for the main
Hello,
first time using python groups (and long time since using any other group for
that matter). This might not be the right group due to wx being involved.
Long story as short as possible. I have an old python script that I did ~10
years ago, and have forgotten basically everything about Pyt
On 08/01/2019 08:29, Arshad Zama wrote:
-- Forwarded message -
From: Arshad Zama
Date: Thu, Jan 3, 2019 at 10:27 PM
Subject: PROBLEM IN LAUNCHING PYTHON...
To:
HELLO SIR,
I'm facing some issue while launching the python ide on windows 8.1 pro.
Kindly help me!!...
What exactly
08.01.19 11:07, Peter Otten пише:
Bob van der Poel wrote:
I need to see if all the items in my list are the same. I was using set()
for this, but that doesn't work if items are themselves lists. So,
assuming that a is a list of some things, the best I've been able to come
up with it:
if a
On Monday, January 7, 2019 at 9:52:03 AM UTC-5, Dave wrote:
> I need to select a Python GUI. It needs to cover all of the desktops
> (Linux, Windows, Apple) and hopefully mobile (Android and Ios). I'm
> looking at Kivy, but have yet to find an example app. that has a native
> looking GUI (Wind
On Jan 7, 2019, at 21:26, Bill Deegan wrote:
> A new SCons release, 3.0.3, is now available on the SCons download page:
>
> https://scons.org/pages/download.html
>
>
> Here is a summary of the changes since 3.0.1:
It would have been good to mention the changes since 3.0.2, whi
On 2019-01-08, MRAB wrote:
> On 2019-01-08 00:47, i...@koeln.ccc.de wrote:
>> You might do something like
>>
>> if len(a) == 0 or all(i == a[0] for i in a[1:]):
>>
> You don't need to check the length of the list because if the list is
> empty, 'all' will return True anyway.
Neat! I expec
Thanks guys for the help on this. As it turns out I have learned new
commands as a result of the question: all() and any() will work perfectly!
The other solutions, as always, are enlightening. And, no, Chris, this is
not homework :)
On Tue, Jan 8, 2019 at 9:31 AM Neil Cerutti wrote:
> On 2019-0
On Tue, 08 Jan 2019 16:48:58 +0200, Serhiy Storchaka wrote:
> 08.01.19 11:07, Peter Otten пише:
>> Bob van der Poel wrote:
>>
>>> I need to see if all the items in my list are the same. I was using
>>> set()
>>> for this, but that doesn't work if items are themselves lists. So,
>>> assuming that
On Tue, 08 Jan 2019 17:15:17 +, Alister wrote:
> On Tue, 08 Jan 2019 16:48:58 +0200, Serhiy Storchaka wrote:
>
>> 08.01.19 11:07, Peter Otten пише:
>>> Bob van der Poel wrote:
>>>
I need to see if all the items in my list are the same. I was using
set()
for this, but that does
On Wednesday, January 2, 2019 at 1:05:44 PM UTC-5, Hüseyin Ertuğrul wrote:
> I don't know the software language at all. What do you recommend to beginners
> to learn Python.
> What should be the working systematic? How much time should I spend every day
> or how much time should I spend on a dail
On Tue, Jan 08, 2019 at 01:05:09PM +1100, Chris Angelico wrote:
> No, because the iteration would never happen. If the list is empty,
> a[1:] is also empty, and i==a[0] will never be evaluated. So it is
> safe. (But I agree that it's not instantly obvious.)
Oh yeah, you're right. I overthought it
On 1/8/19 9:20 AM, Alister wrote:
On Tue, 08 Jan 2019 17:15:17 +, Alister wrote:
On Tue, 08 Jan 2019 16:48:58 +0200, Serhiy Storchaka wrote:
08.01.19 11:07, Peter Otten пише:
Bob van der Poel wrote:
I need to see if all the items in my list are the same. I was using
set()
for this, but
On 1/8/19 2:31 PM, Tobiah wrote:> On 1/8/19 9:20 AM, Alister wrote:
>> On Tue, 08 Jan 2019 17:15:17 +, Alister wrote:
>>
>>> On Tue, 08 Jan 2019 16:48:58 +0200, Serhiy Storchaka wrote:
>>>
08.01.19 11:07, Peter Otten пише:
> Bob van der Poel wrote:
>
>> I need to see if all th
On 08Jan2019 15:28, Dan Sommers <2qdxy4rzwzuui...@potatochowder.com> wrote:
>>> a = [1, 1, 1, 1, 1]
>>> a[1:] == a[:-1]
True
>>> a == a[::-1]
True
>>> a = [1, 2, 3, 4, 3, 2, 1]
>>> a[1:] == a[:-1]
False
>>> a == a[::-1]
True
Looks like Peter's pretty clever after a
On 08Jan2019 15:28, Dan Sommers <2qdxy4rzwzuui...@potatochowder.com> wrote:
>>>>> a = [1, 1, 1, 1, 1]
>>>>> a[1:] == a[:-1]
>>True
>>>>> a == a[::-1]
>>True
>>
>>>>> a = [1, 2, 3, 4, 3, 2, 1]
>>>>> a[1:] == a[:-1]
>>False
>>>>> a == a[::-1]
>>True
There were some issues with my test. After sending the email, I thought
those times couldn't be real. Here are better results:
all_equal(tlst) times = [6.719925760501064e-05] seconds.
all_equal_array_list(tlst) times = [4.2184268278069794e-06] seconds.
import timeit
def all_equal(alist) ->
Hi,
I would start from scratch with this.
1. You have latest Python 2 version.
2. Use virtualenv to create and activate a new virtual environment.
3. pip install wxPython and other dependencies.
4. Get your application running from the command line first and follow up any
DLL exceptions.
5. Use
There was one more error. (smiles ;) Fixed below
def all_equal_array_list(alist) -> bool:
if alist[1:] == alist[:-1]:
return True
return False
def all_equal(alist) -> bool:
if len(alist) == 0 or all(i == alist[0] for i in alist[1:]):
return True
return False
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