On Fri, 26 May 2023 at 10:26, Kevin M. Wilson via Python-list
wrote:
>
> Ok, I'm not finding any info. on the int() for converting a str to an int
> (that specifies a base parameter)?! The picture is of the code I've
> written... And the base 10 paradigm involved?? years = int('y') # store for
On 2023-05-25 22:30, Kevin M. Wilson via Python-list wrote:
Ok, I'm not finding any info. on the int() for converting a str to an int (that specifies
a base parameter)?! The picture is of the code I've written... And the base 10 paradigm
involved?? years = int('y') # store for
"Kevin M. Wilson" writes:
> Ok, I'm not finding any info. on the int() for converting a str to an
> int (that specifies a base parameter)?!
https://docs.python.org/3/library/functions.html#int
> The picture is of the code I've written...
I don't see a picture. The mailing list probably does
On Fri, 26 May 2023 at 09:58, Kevin M. Wilson via Python-list
wrote:
>
> So, why can't a string of an integer be converted to an integer, via
> print(int(str('23.5')))???
23.5 is not an integer, so "23.5" is not the string of an integer.
ChrisA
--
Ok, I'm not finding any info. on the int() for converting a str to an int (that
specifies a base parameter)?! The picture is of the code I've written... And
the base 10 paradigm involved?? years = int('y') # store for calculation
ValueError: invalid literal for int() with base 10: 'y'
What is
On 2023-05-25, Kevin M. Wilson via Python-list wrote:
> Ok, I'm not finding any info. on the int() for converting a str to
> an int (that specifies a base parameter)?!
Where are you looking?
https://docs.python.org/3/library/functions.html#int
> The picture is of the code I've written...
On 24/05/2023 15:37, A KR wrote:
It is perfectly explained in the standards here [1] saying that:
In order to avoid infinite recursion in this method, its implementation should
always call the base class method with the same name to access any attributes
it needs, for example,
On 22/05/2023 22:04, Thomas Wouters wrote:
> I'm pleased to announce the release of Python 3.12 beta 1 (and feature
> freeze for Python 3.12).
>
...
I see a major difference between 3.12.0a7 and 3.12.0b1
Basically in preppy an importer is defined to handle imports of '.prep' files.
This
On 25/05/2023 12:23, Robin Becker wrote:
On 22/05/2023 22:04, Thomas Wouters wrote:
> I'm pleased to announce the release of Python 3.12 beta 1 (and feature
> freeze for Python 3.12).
>
...
I see a major difference between 3.12.0a7 and 3.12.0b1
Basically in preppy an importer is defined
I am wondering whether I have misunderstood the semantics of os.path
relpath or whether it has a bug.
Here is a short test program:
---
from os.path import relpath, split
src_path = 'C:\\lib\\src\\'
vcx_path =
On 25/05/23 7:49 pm, BlindAnagram wrote:
The first of these three results produces an incorrect relative path
because relpath does not strip off any non-directory tails before
comparing paths.
It has no way of knowing whether a pathname component is a directory
or not. It's purely an
On 5/25/23, BlindAnagram wrote:
>
> vcx_path = 'C:\\build.vs22\\lib\\lib.vcxproj'
> src_path = 'C:\\lib\\src\\'
> rel_path = '..\\..\\..\\lib\\src'
>
> [snip]
>
> The first of these three results produces an incorrect relative path
> because relpath does not strip off any non-directory tails
On 2023-05-25 16:53, Eryk Sun wrote:
On 5/25/23, BlindAnagram wrote:
vcx_path = 'C:\\build.vs22\\lib\\lib.vcxproj'
src_path = 'C:\\lib\\src\\'
rel_path = '..\\..\\..\\lib\\src'
[snip]
The first of these three results produces an incorrect relative path
because relpath does not strip off any
Ok, I'm not finding any info. on the int() for converting a str to an int (that
specifies a base parameter)?! The picture is of the code I've written... And
the base 10 paradigm involved?? years = int('y') # store for
calculationValueError: invalid literal for int() with base 10: 'y'What is
We can first convert the string representation of float into float using
float() function and then convert it into an integer using int().So, why can't
a string of an integer be converted to an integer, via
print(int(str('23.5')))???
Perplexed
| print(int(float('23.5'))) |
"When you
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