Amazing how some people bring out the heavy artillery, first! LOL!
If the question was how to remove any initial digits and perhaps whitespace in
a string, it is fairly easy to do without any functions to test if there are
digits before the title. I mean look at initial characters and move
On 2022-06-07 23:24, Dave wrote:
Yes, it was probably just a typeo on my part.
You've misspelled "typo"!
I’ve now fixed the majority of cases but still got two strings that look
identical but fail to match, this time (again by 10cc), “I’m Mandy Fly Me”.
Try printing the asciified string:
I hate regEx and avoid it whenever possible, I’ve never found something that
was impossible to do without it.
> On 8 Jun 2022, at 00:49, dn wrote:
>
> On 08/06/2022 10.18, De ongekruisigde wrote:
>> On 2022-06-08, Christian Gollwitzer wrote:
>>> Am 07.06.22 um 21:56 schrieb Dave:
It
On 08/06/2022 10.18, De ongekruisigde wrote:
> On 2022-06-08, Christian Gollwitzer wrote:
>> Am 07.06.22 um 21:56 schrieb Dave:
>>> It depends on the language I’m using, in Objective C, I’d use isNumeric,
>>> just wanted to know what the equivalent is in Python.
>>>
>>
>> Your problem is also a
rotfl! Nice one!
> On 8 Jun 2022, at 00:24, 2qdxy4rzwzuui...@potatochowder.com wrote:
>
> On 2022-06-07 at 23:07:42 +0100,
> Regarding "Re: How to test characters of a string,"
> MRAB wrote:
>
>> On 2022-06-07 21:23, Dave wrote:
>>> Thanks a lot for this! isDigit was the method I was
Yes, it was probably just a typeo on my part.
I’ve now fixed the majority of cases but still got two strings that look
identical but fail to match, this time (again by 10cc), “I’m Mandy Fly Me”.
I’m putting money on it being a utf8 problem but I’m stuck on how to handle it.
It’s probably the
It depends on the language I’m using, in Objective C, I’d use isNumeric,
just wanted to know what the equivalent is in Python.
If you know the answer why don’t you just tell me and if you don’t, don’t
post!
>>>
>>> People ask home work questions here and we try to teach
On 2022-06-08, Christian Gollwitzer wrote:
> Am 07.06.22 um 21:56 schrieb Dave:
>> It depends on the language I’m using, in Objective C, I’d use isNumeric,
>> just wanted to know what the equivalent is in Python.
>>
>
> Your problem is also a typical case for regular expressions. You can
>
Am 07.06.22 um 23:01 schrieb Christian Gollwitzer:
In [3]: re.sub(r'^\d+\s*', '', s) Out[3]: 'Trinket'
that RE does match what you intended to do, but not exactly what you
wrote in the OP. that would be '^\d\d.' start with exactly two digits
followed by any character.
Christian
Am 07.06.22 um 21:56 schrieb Dave:
It depends on the language I’m using, in Objective C, I’d use isNumeric, just
wanted to know what the equivalent is in Python.
Your problem is also a typical case for regular expressions. You can
create an expression for "starts with any number of digits
On 2022-06-07 at 23:07:42 +0100,
Regarding "Re: How to test characters of a string,"
MRAB wrote:
> On 2022-06-07 21:23, Dave wrote:
> > Thanks a lot for this! isDigit was the method I was looking for and
> > couldn’t find.
> >
> > I have another problem related to this, the following code uses
On 2022-06-07 21:23, Dave wrote:
Thanks a lot for this! isDigit was the method I was looking for and couldn’t
find.
I have another problem related to this, the following code uses the code you
just sent. I am getting a files ID3 tags using eyed3, this part seems to work
and I get expected
On 2022-06-08 at 07:29:03 +1000,
Chris Angelico wrote:
> On Wed, 8 Jun 2022 at 07:24, Barry wrote:
> >
> >
> >
> > > On 7 Jun 2022, at 22:04, Dave wrote:
> > >
> > > It depends on the language I’m using, in Objective C, I’d use isNumeric,
> > > just wanted to know what the equivalent is in
A, ok will do, was just trying to be a brief as possible, will post more
fully in future.
> On 7 Jun 2022, at 23:29, Chris Angelico wrote:
>
> On Wed, 8 Jun 2022 at 07:24, Barry wrote:
>>
>>
>>
>>> On 7 Jun 2022, at 22:04, Dave wrote:
>>>
>>> It depends on the language I’m using, in
On Wed, 8 Jun 2022 at 07:24, Barry wrote:
>
>
>
> > On 7 Jun 2022, at 22:04, Dave wrote:
> >
> > It depends on the language I’m using, in Objective C, I’d use isNumeric,
> > just wanted to know what the equivalent is in Python.
> >
> > If you know the answer why don’t you just tell me and if
> On 7 Jun 2022, at 22:04, Dave wrote:
>
> It depends on the language I’m using, in Objective C, I’d use isNumeric,
> just wanted to know what the equivalent is in Python.
>
> If you know the answer why don’t you just tell me and if you don’t, don’t
> post!
People ask home work questions
Hi,
Found it! The files name had .mp3 at the end, the problem was being masked by
null objects (or whatever) being returned by eyed3.
Checked for null objects and then stripped off the .mp3 and its mostly working
now. I’ve got a few other eyed3 errors to do with null objects but I can sort
Hi,
No, I’ve checked leading/trailing whitespace, it seems to be related to the
variables that are returned from eyed3 in this case, for instance, I added a
check for None:
myTitleName = myID3.tag.title
if myTitleName is None:
continue
Seems like it can return a null object (or none?).
>
It depends on the language I’m using, in Objective C, I’d use isNumeric, just
wanted to know what the equivalent is in Python.
If you know the answer why don’t you just tell me and if you don’t, don’t post!
> On 7 Jun 2022, at 22:08, 2qdxy4rzwzuui...@potatochowder.com wrote:
>
> On 2022-06-07
On 2022-06-07, Dave wrote:
> Thanks a lot for this! isDigit was the method I was looking for and couldn’t
> find.
>
> I have another problem related to this, the following code uses the code you
> just sent. I am getting a files ID3 tags using eyed3, this part seems to work
> and I get
On 2022-06-07, Stefan Ram wrote:
> Dave writes:
>>Example: if "05 Trinket" I want "Trinket"
>
> We're not supposed to write complete solutions,
Okay, wasn't aware of this group policy; will keep it in mind.
--
You're rewriting parts of Quake in *Python*?
MUAHAHAHA
--
On 2022-06-07 at 21:35:43 +0200,
Dave wrote:
> I’m new to Python and have a simple problem that I can’t seem to find
> the answer.
> I want to test the first two characters of a string to check if the
> are numeric (00 to 99) and if so remove the fist three chars from the
> string.
> Example:
Thanks a lot for this! isDigit was the method I was looking for and couldn’t
find.
I have another problem related to this, the following code uses the code you
just sent. I am getting a files ID3 tags using eyed3, this part seems to work
and I get expected values in this case myTitleName
On 2022-06-07, Dave wrote:
> Hi,
>
> I’m new to Python and have a simple problem that I can’t seem to find the
> answer.
>
> I want to test the first two characters of a string to check if the are
> numeric (00 to 99) and if so remove the fist three chars from the string.
>
> Example: if “05
On 08/06/2022 07.35, Dave wrote:
> Hi,
>
> I’m new to Python and have a simple problem that I can’t seem to find the
> answer.
> I want to test the first two characters of a string to check if the are
> numeric (00 to 99) and if so remove the fist three chars from the string.
>
> Example: if
Hi,
I’m new to Python and have a simple problem that I can’t seem to find the
answer.
I want to test the first two characters of a string to check if the are numeric
(00 to 99) and if so remove the fist three chars from the string.
Example: if “05 Trinket” I want “Trinket”, but “Trinket” I
On 07/06/2022 00:28, Israel Brewster wrote:
I have some large (>100GB) datasets loaded into memory in a two-dimensional (X
and Y) NumPy array backed XArray dataset. At one point I want to filter the data
using a boolean array created by performing a boolean operation on the dataset
that is, I
Hi, I'm not an expert on this so this is an educated guess:
You are calling drop=True and I presume that you want to delete the rows
of your dataset that satisfy a condition.
That's a problem.
If the underlying original data is stored in a dense contiguous array,
deleting chunks of it will
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