Can anyone explain why the second print statement below (copied from
'Dive Into Python') generates a syntax error? As I understand
exceptions, the except block should handle the exception, and the
following print statement should execute normally.
>>> try:
fsock = open('/nothere')
except I
Here's the same clip, but run in the command line interpreter. The
error gives a little more info.
>>> try:
... fsock = open('/notthere')
... except IOError:
... print 'The file does not exist, exiting gracefully'
... print 'This line will always print'
File "", line 5
print 'This li
That's good to know. Thanks.
--
http://mail.python.org/mailman/listinfo/python-list
