On 11/11/2022 18:53, DFS wrote:
On 11/11/2022 12:49 PM, Dennis Lee Bieber wrote:
On Fri, 11 Nov 2022 02:22:34 -0500, DFS declaimed the
following:
[(0,11), (1,1), (2,1),
(0,1) , (1,41), (2,2),
(0,9) , (1,3), (2,12)]
The set of values in elements[0] is {0,1,2}
I want the set of max val
On 11/11/2022 07:22, DFS wrote:
[(0,11), (1,1), (2,1),
(0,1) , (1,41), (2,2),
(0,9) , (1,3), (2,12)]
The set of values in elements[0] is {0,1,2}
I want the set of max values in elements[1]: {11,41,12}
def build_max_dict( tups):
dict = {}
for (a,b) in tups:
if (a in di
On 11/11/2022 20:58, Thomas Passin wrote:
On 11/11/2022 2:22 PM, Pancho via Python-list wrote:
On 11/11/2022 18:53, DFS wrote:
On 11/11/2022 12:49 PM, Dennis Lee Bieber wrote:
On Fri, 11 Nov 2022 02:22:34 -0500, DFS declaimed the
following:
[(0,11), (1,1), (2,1),
(0,1) , (1,41), (2,2
On 11/11/2022 19:56, DFS wrote:
Edit: found a solution online:
-
x = [(11,1,1),(1,41,2),(9,3,12)]
maxvals = [0]*len(x[0])
for e in x:
maxvals = [max(w,int(c)) for w,c in zip(maxvals,e)]
print(maxvals)
[11,41,12]
---
On 24/02/2023 18:34, Hen Hanna wrote:
i just wrote a program, which...
within[FunFunPython]
finds: (funny,futon,python)
( 5- and 6- letter words )
(my program uses a Trie, but is pretty simple)
Maybe