evim (easy vim). It is part
of the standard vim distribution (actually it's the same program). Anyway,
I suggest learning the classic modal vim, it's really worth it.
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e in enumerate(lines):
if "ALFA" in line:
code = lines[i + 1].split("=")[1].strip("' \n")
lines[i] = line.replace("ALFA", "BETA%s" % code)
file(name).writelines(lines)
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ange(-a, a+1) for i in xrange(100)]
>>>
>>> # print histogram
... for i in range(-a, a+1):
... print "%+d %s" % (i, '*' * v.count(i))
...
-5 *
-4 *
-3 *
-2 ******
-1 **
+0 *
+1
+2 ***
+3 *
+4
+5
:)
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... [7, 8, 9, 10]]
>>>
>>> a = [[1, 2, 3],
... [4, 5, 6]]
>>>
>>> ab = [[sum(i*j for i, j in zip(row, col)) for col in zip(*b)] for row in a]
>>> ab
[[30, 36, 42, 48], [66, 81, 96, 111]]
Straightforward from the definition of matrix multiplication.
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think of us, non-native English speakers, that don't know slang
words like "noob" that don't even appear in the dictionaries and don't add
anything to your question.
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s damn onliner im looking for.
I know, trying to put complex logic in one line makes you do all that.
Go for the multiliner!
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> NameError: name 'C' is not defined
>
> dictionary is:
>
> DS1v = {'C': 6, 'H': 10, 'O': 5}
Try DS1v['C'] instead of DS1v[C].
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Roberto Bonvallet wrote:
> Alistair King wrote:
>> DS1v = {'C': 6, 'H': 10, 'O': 5}
>
> Try DS1v['C'] instead of DS1v[C].
> updateDS1v(FCas, C, XDS)
> updateDS1v(FHas, H, XDS)
> updateDS1v(FOas, O, XDS)
> updateDS1v(F
Sebastian Busch wrote:
> The task is:
>
> "Remove the first two lines that don't begin with "@" from a file."
awk 'BEGIN {c = 0} c < 2 && !/^@/ {c += 1; next} {print}' < mybeautifulfile
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ly only one -- obvious way to
> do it? 8)
The obvious one is to use enumerate.
TOOWTDI allows less obvious ways to exist.
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le, it's tempting to suggest the best method
> would be string_name[1:-1] and that you don't need a regex.
...or string_name.lstrip('+').rstrip('\n')
I bet he doesn't need a regexp!
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rser know which colon terminates the
'for' in the following example:
for i in 2:3:4:
...
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turn is a reserved keyword. You cannot have a variable with that name.
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t;db = "homebase_zingers"
> );
>
>
> but even when I have that, I still get the same error.
Could you please copy and paste the exact code that is triggering the
error, and the exact error message?
(BTW, in Python you don't need to end your sta
iff)
['0.4', '0.1', '-0.2', '-0.01', '0.11', '0.5', '-0.2', '-0.2', '0.6',
'-0.1', '0.2', '0.1', '0.1', '-0.45', '0.15', '-0.3', '-0.2&#x
.." should have supported this! <:o)
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arguments and return the following list:
>
> ['e', 'r', 'w', 'q', 't', 'y', 'u', 'i', 'o', 'p']
>>> mainlist = list('qwertyuiop')
>>> orderinglist = [3, 4, 2, 1]
>
s mainlist[i - 1].
If orderinglist is [3, 4, 2, 1], then [mainlist[i - 1] for i in
orderinglist] is:
[mainlist[3 - 1], mainlist[4 - 1], mainlist[2 - 1], mainlist[1 - 1]]
Remember that indexing starts from 0.
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;a') and 2(type 'b') are connected,3 and 5 are connected
> and so on.
> I am not able to figure out how to do this.Any pointers would be helpful
I don't understand very well what you want to do. Could you explain
it more clearly, with an example?
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e
'sin' : (self.arbtrandef, (2, 3)),
'exp' : (self.arbtrandef, (2, 4)),
'pwl' : (self.pwldef, ()),# empty tuple represented by ()
'sffm' : (self.arbtrandef, (5, 0)),
}
for (fname, (func, args)) in alldict.items(): # items unpacked directly
func(fname, *args)
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d for j in d if i < j]
>>> for i, j in pairs:
... cartesian_product = [(x, y) for x in d[i] for y in d[j]]
... print i + j, cartesian_product
...
ac [(1, 6), (1, 7), (2, 6), (2, 7)]
ab [(1, 3), (1, 4), (1, 5), (2, 3), (2, 4), (2, 5)]
bc [(3, 6), (3, 7), (4, 6), (4, 7), (5, 6), (5, 7)]
You can do whatever you want with this cartesian product inside the loop.
> >Finally i want to check each pair if it is present in the file,whose
> >format i had specified.
I don't understand the semantics of the file format, so I leave this
as an exercise to the reader :)
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> > aab
>
> Right. But that wasn't the question :p
The question was about elegance, and elegance is when someone asks "do
something 4 times for 5 strings of length 3" and you solve it for "do
something n times for m strings
Ravi Teja <[EMAIL PROTECTED]> said:
> I *like* 1..5 (ada, ruby) instead of range(5). If I had macros, I would
> have done it myself for *my* code.
You can write your own preprocessor to handle things like that.
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imho <[EMAIL PROTECTED]>:
> map(lambda x:"" , [i for i in [a,b,c] if i in ("None",None) ])
You don't need map when using list comprehensions:
["" for i in [a, b, c] if i in ("None", None)]
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a good idea to
try to reuse modules that are good at what they do.
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k", you just have to omit
the voice method for the dog class: it will be inherited from creature.
If you want dog.voice() to do something else, you can call superclass'
method like this:
def voice(self):
creature.voice(self)
print "brace your self"
any_other_magic()
HTH
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so i could access every method of instances of C
Something like this?
>>> class C:
... def f1(self):
... print "i'm one"
... def f2(self):
... print "i'm two"
...
>>> obj = C()
>>> d = {'one': obj.f1,
bash-like syntax, you should really consider using bash :)
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gt;>> l =
>>> [[['r00','g00','b00'],['r01','g01','b01']],[['r10','g10','b10'],['r11','g11','b11']]]
>>> def get_deepest(l, n):
... if isinstance(l[0], list):
... return [get_deepest(s, n) for s in l]
... else:
... return l[n]
...
>>> get_deepest(l, 0)
[['r00', 'r01'], ['r10', 'r11']]
>>> get_deepest(l, 1)
[['g00', 'g01'], ['g10', 'g11']]
>>>
n is the chosen index.
HTH.
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Please paste here the errors you get, and paste also the relevant code (not
the whole program) that triggers that error.
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build a 1-element tuple, you have to put a trailing comma:
elif opt in ("--notfound", ):
but it would be clearer if you just use:
elif opt == "--notfound":
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st by
appending a underscore to the word: pass_, return_, ...
wink_
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ableString class that would be a better approach:
http://docs.python.org/lib/module-UserString.html
Anyway, I bet that what Martin wants to do can be done by using only string
methods :)
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: bob_apple = (1, 2, ..., 9), you don't need to initialize
bob_apple with an empty tuple.
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er (worse) way, just for fun:
>>> from itertools import cycle
>>> input = [1, 2, 3, 4, 5, 6]
>>> wanted = [x * sign for x, sign in zip(input, cycle([1, -1]))]
>>> wanted
[1, -2, 3, -4, 5, -6]
Cheers,
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ESTED
program = open(fileName)
for line in program:
while line.rstrip("\n").endswith("_"):
line = line.rstrip("_ \n") + program.readline()
do_the_magic()
Cheers,
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SeanDavis12 wrote:
> I have a dictionary like:
>
> {"a":1, "b":2}
>
> and I want to call a function:
>
> def func1(a=3,b=4):
>print a,b
>
> so that I get a=1,b=2, how can I go about that?
func1(**yourdict)
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attern in Python. You should
do it like this:
for item in a:
output.writerow([item])
> Second, there is a significant delay (5-10 minutes) between when the
> program finishes running and when the text actually appears in the
> file.
Try closing the file explicitly.
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Neil Cerutti wrote:
> On 2006-11-29, Roberto Bonvallet <[EMAIL PROTECTED]> wrote:
>> BTW, iterating over range(len(a)) is an anti-pattern in Python.
>
> Unless you're modifying elements of a, surely?
enumerate is your friend :)
for n, item in enumerate(a):
way, if possible; I know that I could test for a.id.
Define a method called __nonzero__ that returns True or False.
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gt; but nothing..
type() doesn't return a string, it returns a type object.
You should try this:
if isinstance(artistList, list):
...
Cheers,
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ern" tends to imply that it is always
> wrong.
Right, I should have said: "iterating over range(len(a)) just to obtain the
elements of a is not the pythonic way to do it".
Cheers,
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newsgroup, most people said they preferred #!/usr/bin/env python over
#!/usb/bin/python for the shebang line. See http://tinyurl.com/yngmfr .
Best regards.
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interpreter.
>
> See http://www.python.org/dev/peps/pep-0263/
The -*- syntax is emacs-style. The encoding directive is anything that
matches r"coding[=:]\s*([-\w.]+)". The docs recommend to use either
emacs-style or vim-style. See http://docs.python.org/ref/encodings.html
Chee
immediately noticed them and came up with an example to
raise both issues is a indicator of how easy it would be to customize the
script :)
Cheers!
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s.python.org/lib/module-re.html:
This module provides regular expression matching operations
*similar* to those found in Perl.
Similar != the same. See http://docs.python.org/lib/re-syntax.html for
details about valid syntax for regular expressions in Python.
Cheers,
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Fredrik Lundh wrote:
[...]
> this is why e.g.
>
>string[:len(prefix)] == prefix
>
> is often a lot faster than
>
>string.startswith(prefix)
This is interesting. In which cases does the former form perform better?
[I won't stop using str.startswith anyway
Andy Dingley wrote:
> I need to generate a set (lots of intersections involved), but then I
> need to display it sorted
>
>lstBugsChanged = [ bugId for bugId in setBugsChanged ]
>lstBugsChanged.sort()
In Python > 2.4:
sorted(setBugsChanged)
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I wrote:
> In Python > 2.4:
lastline.replace(">", ">=")
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Andy Dingley wrote:
> Out of interest, whats the Pythonic way to simply cast (sic) the set to
> a list, assuming I don't need it sorted? The list comprehension?
mySet = set(myList)
myList = list(mySet)
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k) in cartesian_product(l1, l2, l3):
print "do something with", i, j, k
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;ofile.write(line)
This should work (untested):
infile = open('filename', 'r')
outfile = open('otherfile', 'w')
for line in infile:
outfile.write(line.replace('—', '--'))
But I think the best approach is to use a existing aplication or library
that solves the problem. recode(1) can easily convert to and from HTML
entities:
recode html..utf-8 filename
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ndant?
This could be more convenient to you, but certainly not pythonic.
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e the new conditional syntax because he felt it was
needed or just to avoid typing a couple of extra lines. He did it just to
avoid people keep using the ugly and error-prone "a and b or c" idiom. See
the related PEP: http://www.python.org/dev/peps/pep-0308/
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Chao wrote:
> My Bad, the time used by python is 0.46~0.49 sec,
> I tried xrange, but it doesn't make things better.
Actually it does: it doesn't waste time and space to create a big list.
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> a, consequat ut, elementum ac, libero. Donec malesuada lacus vel quam. Ut
a
> massa vel velit fringilla rutrum. Maecenas massa sem, vulputate non,
> lacinia eu, cursus ut, urna. Donec ultrices sollicitudin nunc. Sed vel
arcu
> in lacus posuere faucibus. Lorem ipsum
) to be available.
list(my_arg).index(...)
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e off the last item:
>>
>> for line in list(open("file"))[:-1]:
>> print line
>>
>>
>
> hi
> would it be a problem with these methods if the file is like 20Gb in
> size...?
The second one would be a problem, since
o):
File "", line 1
def a-star(self, nodeFrom, nodeTo):
^
SyntaxError: invalid syntax
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n't document those private internals.
Or document that they must not be accessed directly.
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x27;t see a
> way of actually running the function.
Try this:
def f(x):
print "Calling f with arg %s" % x
def g(x):
print "Calling g with arg %s" % x
def h(x):
print "Calling h with arg %s" % x
import random
functions = [f, g, h]
for i in range(10):
On 20 jul, 18:50, Alex Popescu <[EMAIL PROTECTED]> wrote:
> If you just want to iterate over your dict in an ordered manner than all
> you have to do is:
>
> for k in my_dict.keys().sort():
> # rest of the code
sort() returns None, so this code won't work either.
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e new list.
Try this:
c = copy.copy(a.keys())
c.sort()
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[EMAIL PROTECTED] wrote:
> s = "jk hij ght"
> print "".join(s.split(" "))
"".join(s.split()) is enough.
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On Aug 9, 6:11 pm, Lee Sander <[EMAIL PROTECTED]> wrote:
> I would like to define a new variable which is not predefined by me.
> For example,
> I want to create an array called "X%s" where "%s" is to be determined
> based on the data I am processing.
Use a dictionary.
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:
n = int(n)
k = int(k)
if n <= 0:
raise ValueError("Wrong value of n: %d" % n)
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lists of 1000 elements, so you're not
actually
measuring only the numeric computations.
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while j < 1000:
...
I'm no expert on Python optimization either, so I cannot guarantee
that both are
the best way to write this algorithm.
> > > [...]
> > > m=j+1
This step also doesn't occur in the Matlab
x)
> period = Slab(accu)
Better to use the `sum' builtin and a generator expression:
period = Slab(sum(Material(x)) for x in numbers)
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rn the same result as integer addition. However if either x or y
> is None, these operations return None.
No need to create a new class:
try:
result = a * b
except TypeError:
result = None
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the actual code. It is easier,
less error prone and more useful to copy and paste them instead of
writing some pseudocode. Maybe the repeated index i is a typo you
made when writing this post and the original code is correct, but we
don't have any way to know that.
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--
; pinguino
Frühstück -> Fruehstueck
I'd like that web applications (e.g. blogs) took into account these
conventions when creating URLs from the title of an article.
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fact(x):
r = re.compile(r"%d ! = (\d+)" % x)
for line in urllib.urlopen("http://www.google.cl/search?q=%d%%21";
% x):
m = r.search(line)
if m:
return int(m.group(1))
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e URL is .../ValparaSoViADelMar. And if I wrote a blog entry
about pingüinos and ñandúes, it would appear probably as .../ping-inos-
and-and-es. Ugly and off-topic :)
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oupby(enumerate(reversed(str(x))), lambda (n, i): n//3))[::-1]
'12.332.321'
>>>
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On 31 oct, 22:21, Paul Rubin <http://[EMAIL PROTECTED]> wrote:
> def convert(n):
>assert type(n) in (int,long)
I'd replace this line with n = int(n), more in the spirit of duck
typing.
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7;
>>> a.split("-")[-1][:-len(".src.rpm")]
'2.3.4'
>>> ".".join(map(str, range(2, 5)))
'2.3.4'
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3],
... [0, 0, 0, 5]]
>>> min(min(x for x in row if x > 0) for row in matrix)
5
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Victor Polukcht wrote:
> My actual problem is i can't get how to include space, comma, slash.
Post here what you have written already, so we can tell you what the
problem is.
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e pattern:
>
> import re
> p = re.compile('X.*?Y', re.DOTALL)
> print re.sub(p, 'Z', 'Xab\ncdY')
>
> Still the question - my fault or a bug?
Your fault. According to the documentation [1], the re.sub function takes
a count as a fourth
OSE::#.
This fails when the code already has the strings "#::OPEN::#" and
"#::CLOSE::" in it.
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es included" solution that doesn't involve
> reinventing the wheel?
recode is good for this kind of things:
$ recode latin1..html -d mytextfile
It seems that there are recode bindings for Python:
$ apt-cache search recode | grep python
python-bibtex - Python inte
k with raise.
I completely agree.
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l return 7.125. Is it close enough?
Finding a better estimation is more a math problem than a Python one.
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On Dec 8, 4:19 am, [EMAIL PROTECTED] wrote:
> With properties, attributes and methods seem very similar. I was
> wondering what techniques people use to give clues to end users as to
> which 'things' are methods and which are attributes.
Methods are verbs, attributes are n
ision
This forces all divisions to yield floating points values:
>>> 1/3
0
>>> from __future__ import division
>>> 1/3
0.33331
>>>
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rnt about it anywhere.
I started
to do it spontaneously in order to tell apart end-of-sentence periods
from abbreviation
periods. Anyway, I don't think it's something people should be forced
to do.
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[x/sum(x**2 for x in v)**0.5 for x in v]
or, in order to avoid computing the norm for each element:
def u(v):
return (lambda norm: [x/norm for x in v])(sum(x**2 for x in v)
**0.5)
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