Re: Execution speed question
On Mon, 28 Jul 2008 16:48:28 +0200, Suresh Pillai wrote: Okay, please consider this my one absolutely stupid post for the year. I'd like to pretend it never happened but unfortunately the web doesn't allow that. Having never used sets, I unfort read something that lead to it, but ... Okay, got some sleep and what I meant to ask, although equally basic, but not silly: For sets, I presume they are built on top of or like dicts, and there is nothing crazy in the low level implementation so that I can be guaranteed that if I don't alter the set, then the order, although arbitrary, will be maintained in successive iterations over the contents? -- http://mail.python.org/mailman/listinfo/python-list
Re: Execution speed question
On Fri, 25 Jul 2008 08:08:57 -0700, Iain King wrote: On Jul 25, 3:39 pm, Suresh Pillai [EMAIL PROTECTED] wrote: That's a good comparison for the general question I posed. Thanks. Although I do believe lists are less than ideal here and a different data structure should be used. To be more specific to my case: As mentioned in my original post, I also have the specific condition that one does not know which nodes to turn ON until after all the probabilities are calculated (lets say we take the top m for example). In this case, the second and third will perform worse as the second one will require a remove from the list after the fact and the third will require another loop through the nodes to build the new list. So you need to loops through twice regardless? i.e. loop once to gather data on off nodes, do some calculation to work out what to turn on, then loop again to turn on the relevant nodes? If so, then I think the functions above remain the same, becoming the 2nd loop. Every iteration you do a first loop over the off_nodes (or them all for (1)) to gather the data on them, perform your calculation, and then perform one of the above functions (minus the setup code at the begining; basically starting at the 'for') as a second loop, with the goes_on function now returning a value based on the calculation (rather than the calculation itself as I had it). Performance should be similar. Iain If do I settle on an explicit loop to remove the nodes turned ON, then I realised this weekend that I could do this in the next iteration of the simulation (first loop above) and save some iteration overhead (the if checking will still be there of course). And thanks for pointing out that constructing a new list, for long lists, is faster than simple removal. It's obvious but I never really thought of it; good tip. -- http://mail.python.org/mailman/listinfo/python-list
Re: Execution speed question
On Fri, 25 Jul 2008 05:46:56 -0700, Iain King wrote: or 3. build a new list every iteration intead of deleting from the old one: while processing: new_off_list = [] for x in off_list: if goes_on(x): on_list.append(x) else: new_off_list.append(x) off_list = new_off_list generation += 1 Iain Or 4, since the order of my nodes doesn't matter: swap the node to be deleted with the last node in the list and then remove the last node of the list. This is the fastest to date, if using native structures, for low number nodes being deleted per cycle (def if only deleting one). -- http://mail.python.org/mailman/listinfo/python-list
Re: Execution speed question
On Mon, 28 Jul 2008 10:44:18 +0200, Suresh Pillai wrote: Since I am doing A LOT of loops over the nodes and the number of nodes is also huge, my concern using sets is that in order to iterate over the set in each step of my simulation, the set items need to be converted to a list every time. So while removal from a set is much cheaper than say from a list, what about this conversion overhead in order to iterate over the items. I could of course use the old trick of using a dictionary with 'None' values and then using iterkeys(). But I thought sets were supposed to replace this. So maybe I should be asking a more basic question: is there any way to iterate over the items in a set other than converting to a list or using the pop() method. -- http://mail.python.org/mailman/listinfo/python-list
Re: Execution speed question
On Mon, 28 Jul 2008 15:04:43 +0200, Suresh Pillai wrote: On Mon, 28 Jul 2008 10:44:18 +0200, Suresh Pillai wrote: Since I am doing A LOT of loops over the nodes and the number of nodes is also huge, my concern using sets is that in order to iterate over the set in each step of my simulation, the set items need to be converted to a list every time. So while removal from a set is much cheaper than say from a list, what about this conversion overhead in order to iterate over the items. I could of course use the old trick of using a dictionary with 'None' values and then using iterkeys(). But I thought sets were supposed to replace this. So maybe I should be asking a more basic question: is there any way to iterate over the items in a set other than converting to a list or using the pop() method. Okay, please consider this my one absolutely stupid post for the year. I'd like to pretend it never happened but unfortunately the web doesn't allow that. Having never used sets, I unfort read something that lead to it, but ... -- http://mail.python.org/mailman/listinfo/python-list
Execution speed question
I am performing simulations on networks (graphs). I have a question on speed of execution (assuming very ample memory for now). I simplify the details of my simulation below, as the question I ask applies more generally than my specific case. I would greatly appreciate general feedback in terms of computing and of course considerations specific to implementation in Python. The nodes in my network may be ON or OFF. The network starts off with all nodes in the OFF state. I loop through the nodes. For each node that is OFF, I consider some probability of it turning ON based on the states of its neighbours. I MUST GO THROUGH ALL NODES BEFORE DECIDING WHICH ONES TO TURN ON. So my question is whether it is faster to 1. loop through a list of ALL nodes and check for OFF nodes using ifs or to 2. loop through a container of OFF nodes and remove from this when they turn ON The second would result in looping through less nodes, especially as the simulation progresses, but how does the cost of removal compare with cheap ifs and would the extra memory usage affect performance. I an appreciate that the cost of the if check, the number of nodes, and the type of container I use will come into the answer. In my case, the ifs are cheap boolean queries (whether the node is ON or OFF). The number of nodes is very large: millions for sure, maybe tens of millions. If considering (2), take note of my BOLD text above, which means I can't remove nodes as I iterate through them in the main loop. I naturally started coding with (2), but couldn't decide on the best data structure for python. A set seemed ideal for speedy removal, but then I can't iterate through them with out popping. An ordered list? Some creative solution with numpy arrays? There is also the complication that since we are in interpreted python, what is theoretically the best data structure may not in reality be optimal unless it is a default system object or coded externally in a compiled module. Of course, I will start experimenting to see what the execution difference is, but I would appreciate some suggestions from others re which is best and also on best data structure for (2). I'm not a newbie, so you can get technical with me python-wise and algorithm wise. I realise it is a 'basic' question, but it is something that I have always wondered about (cheap ifs versus extra structure) and with the number of nodes I am considering, it actually becomes an issue. Many Thanks, Suresh -- http://mail.python.org/mailman/listinfo/python-list
Re: Execution speed question
That's a good comparison for the general question I posed. Thanks. Although I do believe lists are less than ideal here and a different data structure should be used. To be more specific to my case: As mentioned in my original post, I also have the specific condition that one does not know which nodes to turn ON until after all the probabilities are calculated (lets say we take the top m for example). In this case, the second and third will perform worse as the second one will require a remove from the list after the fact and the third will require another loop through the nodes to build the new list. -- http://mail.python.org/mailman/listinfo/python-list
Re: Execution speed question
On Fri, 25 Jul 2008 16:51:42 +0200, Fredrik Lundh wrote: Unless I'm missing something, your example keeps going until it's flagged *all* nodes as on, which, obviously, kills performance for the first version as the probability goes down. The OP's question was about a single pass (but he did mention as the simulation progresses, so I guess it's fair to test a complete simulation.) I was referring to multiple passes as in Iain' test cases. Although not necessarily till all nodes are ON, let's say to to a large proportion at least. -- http://mail.python.org/mailman/listinfo/python-list
