My client in Jersey City, NJ 07302 is looking for a Python Developer. Below
is the job description:
Job Summary:
This is a programming position in the technical department of Advance
Internet, working on application development, application integration,
automated testing and deployment of appli
I'm starting out with Python 3.5. My current frustration is with:
>>> math.sqrt(25)
Traceback (most recent call last):
File "", line 1, in
math.sqrt(25)
NameError: name 'math' is not defined
>>>
Advice?
Jack
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I want to let the name of an attribute be the string value of a variable. Here
is some code:
class Object(object): pass
A = Object()
s = 'attr'
A. = 1
The last line denotes the variable value by (not a python form). What I
want is to have A.attr = 1, but 'attr' determined by the value of s.
I am looping as for L in file.readlines(), where file is csv.
L is a list of 3 items, eg, [{'a':1, 'b':2}, [1,2,3], 10] Note that the first
item is a dir and 2nd is a list, so parsing with split doesn't work. Is there
a way to convert L, which is a string, to the list of 3 items I want?
--
ht
On Saturday, October 5, 2013 7:24:39 PM UTC-6, Tim Chase wrote:
> On 2013-10-05 18:08, Harvey Greenberg wrote:
>
> > I am looping as for L in file.readlines(), where file is csv.
>
> >
>
> > L is a list of 3 items, eg, [{'a':1, 'b':2}, [1,2,3]
On Sunday, October 6, 2013 10:41:33 AM UTC-6, Harvey Greenberg wrote:
> On Saturday, October 5, 2013 7:24:39 PM UTC-6, Tim Chase wrote:
>
> > On 2013-10-05 18:08, Harvey Greenberg wrote:
>
> >
>
> > > I am looping as for L in fi
On Saturday, October 5, 2013 7:08:08 PM UTC-6, Harvey Greenberg wrote:
> I am looping as for L in file.readlines(), where file is csv.
>
>
>
> L is a list of 3 items, eg, [{'a':1, 'b':2}, [1,2,3], 10] Note that the first
> item is a dir and 2nd is a li
Matt wrote:
> I am attempting to reformat a string, inserting newlines before certain
> phrases. For example, in formatting SQL, I want to start a new line at
> each JOIN condition. Noting that strings are immutable, I thought it
> best to spllit the string at the key points, then join with '\n'.
శ్రీనివాస wrote:
> Hai friends,
> Can any one tell me how can i remove a character from a unocode text.
> కల్&హార is a Telugu word in Unicode. Here i want to
> remove '&' but not replace with a zero width char. And one more thing,
> if any whitespaces are there before and after '&' char, the text
Hi,
Suppose I write
if x in ("abc", "def", "xyz"):
doStuff()
elif x in ("pqr", "tuv", "123"):
doOtherStuff()
elif ...
etc.
When is python building the tuples? Does it need to build the tuple
every time it comes through this code? Or do
Fredrik Lundh wrote:
> when in doubt, ask the compiler:
MTD wrote:
> >>> dis.dis(cod)
Thanks so much guys! Python just gets cooler every day!
David
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On May 22, 2:45 pm, "sim.sim" <[EMAIL PROTECTED]> wrote:
> Hi all.
> i'm faced to trouble using minidom:
>
> #i have a string (xml) within CDATA section, and the section includes
> "\r\n":
> iInStr = '\n\n'
>
> #After i create DOM-object, i get the value of "Data" without "\r\n"
>
> from xml.dom im
range(0x20, 0xD7FF), iMessage)- Hide quoted
> text -
>
> - Show quoted text -
You need to explicitly convert the string of UTF8 encoded bytes to a
Unicode string before parsing e.g.
unicodestring = unicode(encodedbytes, 'utf8')
Unless I messed up copying and pasting, your
s not valid XML. It misses a xmlns:text namespace
> declaration. So you won't be able to parse it regardless of what parser you
> use.
>
> Diez- Hide quoted text -
>
> - Show quoted text -
The example is valid well-formed XML. It is permitted to use the ":"
character in element names. Whether one should in a non namespace
context is a different matter.
Harvey
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Hugo Ferreira wrote:
> Hi!
>
> I'm trying to do a search-replace in places where some groups are
> optional... Here's an example:
>
> >> re.match(r"Image:([^\|]+)(?:\|(.*))?", "Image:ola").groups()
> ('ola', None)
>
> >> re.match(r"Image:([^\|]+)(?:\|(.*))?", "Image:ola|").groups()
> ('ola', '')
Hugo Ferreira wrote:
> Hi!
>
> I'm trying to do a search-replace in places where some groups are
> optional... Here's an example:
>
> >> re.match(r"Image:([^\|]+)(?:\|(.*))?", "Image:ola").groups()
> ('ola', None)
>
> >> re.match(r"Image:([^\|]+)(?:\|(.*))?", "Image:ola|").groups()
> ('ola', '')
Victor Polukcht wrote:
> My pattern now is:
>
> (?P[^(]+)(?P\d+)\)\s+(?P\d+)
>
> And i expect to get:
>
> var1 = "Unassigned Number "
> var2 = "1"
> var3 = "32"
>
> I'm sure my regexp is incorrect, but can't understand where exactly.
>
> Regex.debug shows that even the first block is incorrect.
>
Rickard Lindberg wrote:
> I see two potential problems with the non regex solutions.
>
> 1) Consider a line: "foo (bar)". When you split it you will only get
> two strings, as split by default only splits the string on white space
> characters. Thus "'bar' in words" will return false, even though
Rickard Lindberg wrote:
> I see two potential problems with the non regex solutions.
>
> 1) Consider a line: "foo (bar)". When you split it you will only get
> two strings, as split by default only splits the string on white space
> characters. Thus "'bar' in words" will return false, even though
Hello
Sending mail with certain characters in the body causes mail never to
arrive. Why?
e.g if body text has a fullstop "." mail never arrives.
I'm using python 4.2 on windows.
Harvey
#
]* portion of my
> regex is being ignored, so only one match is being returned, starting
> at the first and ending at the end of the text, when it should
> end at the first . For this example, it should return three
> matches, one for each div.
>
> Is what I'm trying to do possible with Python's Regex library? Is
> there an error in my Regex?
>
> Thanks,
> Chris
print re.findall(r'<%s(?=[\s/>])[^>]*>' % 'div', r)
["", "", ""]
HTH
Harvey
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t;':
#strip off the quotes and normalise spaces
ret.append(' '.join(x[1:-1].split()))
else:
ret.append(x)
return ret
query = ' " Some words" withand "withoutquotes " '
print findwords(query)
Running this gives
['Some words', 'with', 'and', 'without quotes']
HTH
Harvey
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2009/7/4 Andre Engels :
> On Sat, Jul 4, 2009 at 9:33 AM, mclovin wrote:
>> Currently I need to find the most common elements in thousands of
>> arrays within one large array (arround 2 million instances with ~70k
>> unique elements)
>>
>> so I set up a dictionary to handle the counting so when I a
2009/7/4 Patrick Sabin :
> If someone has another idea of taking a snapshot let me know. Using VMWare
> is not a
> very elegant way in my opinion.
Someone implemented the same idea for Java a while ago. They called it
"omniscient debugging"; you can find details at
http://www.lambdacs.com/debu
2009/7/4 Steven D'Aprano :
> On Sat, 04 Jul 2009 13:42:06 +, Steven D'Aprano wrote:
>
>> On Sat, 04 Jul 2009 10:55:44 +0100, Vilya Harvey wrote:
>>
>>> 2009/7/4 Andre Engels :
>>>> On Sat, Jul 4, 2009 at 9:33 AM, mclovin wrote:
>>&
2009/7/6 Xavier Ho :
> Why is version B of the code faster than version A? (Only three lines
> different)
Here's a guess:
As the number you're testing gets larger, version A is creating very
big list. I'm not sure exactly how much overhead each list entry has
in python, but I guess it's at least
2009/7/8 Dhananjay :
> I wanted to sort column 2 in assending order and I read whole file in array
> "data" and did the following:
>
> data.sort(key = lambda fields:(fields[2]))
>
> I have sorted column 2, however I want to count the numbers in the column 2.
> i.e. I want to know, for example, how
2009/7/12 Cameron Pulsford :
> My question is, is it possible to combine those two loops? The primes
> generator I wrote finds all primes up to n, except for 2, 3 and 5, so I must
> check those explicitly. Is there anyway to concatenate the hard coded list
> of [2,3,5] and the generator I wrote so
2009/7/13 seldan24 :
> Thank you both for your input. I want to make sure I get started on
> the right track. For this particular script, I should have included
> that I would take the exception contents, and pass those to the
> logging module. For this particular script, all exceptions are fata
2009/7/13 Aaron Scott :
>> BTW, you should derive all your classes from something. If nothing
>> else, use object.
>> class textfile(object):
>
> Just out of curiousity... why is that? I've been coding in Python for
> a long time, and I never derive my base classes. What's the advantage
> to der
I think it's great that for built-in types such as int and str, backward
compatibility of type hinting annotations is baked into python 3.0 to 3.4. In
fact, I *thought* python 3.0 to 3.4 would *ignore* annotations, but it
doesn't...
I'm struggling to create something backward compatible that re
This pattern seems to work:
import sys
if sys.version_info[0] < 3:
raise RuntimeError("Must use at least python version 3")
# The 'typing' module, useful for type hints, was introduced in python 3.5
if sys.version_info[1] >= 5:
from typing import Optional
optional_float = Optional[fl
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