Re: subprocess.Popen() output to logging.StreamHandler()

2008-04-10 Thread svensven
Thomas Dimson wrote: > On Apr 10, 8:11 am, "sven _" <[EMAIL PROTECTED]> wrote: >> My goal is to have stdout and stderr written to a logging handler. >> This code does not work: >> >> # START >> import logging, subprocess >> ch = logging.StreamHandler() >> ch.setLevel(logging.DEBUG) >> subp

Re: subprocess.Popen() output to logging.StreamHandler()

2008-04-10 Thread svensven
Vinay Sajip wrote: > On Apr 10, 1:11 pm, "sven _" <[EMAIL PROTECTED]> wrote: >> My goal is to have stdout and stderr written to a logginghandler. > > Thomas was almost right, but not quite - you can't call info on a > Handler instance, only on a Logger instance. The following script: Yes, but