while 1:
runner = os.popen("tracert -d www.hello.com")
o=runner.read()
print(o)
runner.close()
runner = os.popen("tracert -d www.hello.com")
o=runner.read()
print(o)
runner.close()
runner = os.popen("tracert -d www.hello.com")
o=runner.read()
print(o)
runner.close()
after running over 1 hour, it
Process PoolWorker-1:
Traceback (most recent call last):
File "C:\Python27\lib\multiprocessing\process.py", line 258, in _bootstrap
self.run()
File "C:\Python27\lib\multiprocessing\process.py", line 114, in run
self._target(*self._args, **self._kwargs)
File
i fixed by replace("","\\")
On Monday, October 30, 2017 at 11:16:02 AM UTC+8, Igor Korot wrote:
> Hi,
>
> On Sun, Oct 29, 2017 at 10:03 PM, Ho Yeung Lee <jobmatt...@gmail.com> wrote:
> > i discover when
> > it
> > decode("\\&qu
it seems that it read csv file
from "\\" to ""
On Monday, October 30, 2017 at 11:03:57 AM UTC+8, Ho Yeung Lee wrote:
> i discover when
> it
> decode("\\",1,2)
> in interactive console
> is [
>
> but decode in big project
> it see as
i discover when
it
decode("\\",1,2)
in interactive console
is [
but decode in big project
it see as
decode(r"\\",1,2)
[[
it double
On Monday, October 30, 2017 at 9:51:01 AM UTC+8, Ho Yeung Lee wrote:
> if run these function to decode in python interactive console,
>>> from Crypto.Cipher import AES
>>>
>>> key = 'mysecretpassword'
>>> plaintext = 'Secret Message A'
>>> encobj = AES.new(key, AES.MODE_ECB)
>>> ciphertext = encobj.encrypt("hello")
Traceback (most recent call last):
File "", line 1, in
File
if run these function to decode in python interactive console,
it can decode correct,
but when run with a big project, it append a letter Y
On Monday, October 30, 2017 at 9:48:36 AM UTC+8, Ho Yeung Lee wrote:
> def leftrotate(l, n):
> return l[n:] + l[:n]
>
> def righ
def leftrotate(l, n):
return l[n:] + l[:n]
def rightrotate(l, n):
return l[-n:] + l[:-n]
def encode(s, k, kk):
l = [ord(i) for i in s]
return leftrotate(''.join([chr(i + k) for i in l]), kk)
def decode(s, k, kk):
l = [ord(i) for i in rightrotate(s, kk)]
return
http://treelib.readthedocs.io/en/latest/examples.html
tree = Tree()
#create root
tree.create_node((0,0), "root")
result = [aa[0]]
previousnode = (0,0)
>>> #create root
... tree.create_node((0,0), "root")
Traceback (most recent call last):
File "", line 2, in
File
my code can run without error,
you can try to download one of face from search keyword "face"
and try this script
On Tuesday, August 15, 2017 at 4:33:51 AM UTC+8, jlad...@itu.edu wrote:
> On Monday, August 14, 2017 at 12:30:21 PM UTC-7, Ho Yeung Lee wrote:
> > https://gist.gi
)+1
colortolocation[eachcolor] = locationsgroup
On Tuesday, August 15, 2017 at 4:33:51 AM UTC+8, jlad...@itu.edu wrote:
> On Monday, August 14, 2017 at 12:30:21 PM UTC-7, Ho Yeung Lee wrote:
> > https://gist.github.com/hoyeunglee/df7e6cb9b76c576b26fd2bb2b26bfe2f
> >
> >
https://gist.github.com/hoyeunglee/df7e6cb9b76c576b26fd2bb2b26bfe2f
sample image
https://drive.google.com/file/d/0Bxs_ao6uuBDUY09qM1JMWS1Ob0k/view?usp=sharing
would like to rectangle bound the eye ,mouth corner etc
which detected by harris corner
but using kmeans can not rectangle the red area
def mse(imageA, imageB):
err = np.sum((imageA.astype("float") - imageB.astype("float")) ** 2)
err /= float(imageA.shape[0] * imageA.shape[1])
return err
original = cv2.imread("C:\\Users\\hello\\Documents\\words\\" + xx)
later = cv2.imread("C:\\Users\\hello\\Documents\\words\\"+ yy)
On Friday, August 4, 2017 at 10:08:56 PM UTC+8, Ho Yeung Lee wrote:
> i had changed to use kmeans
>
> https://gist.github.com/hoyeunglee/2475391ad554e3d2b2a40ec24ab47940
>
> i do not know whether write it correctly
> but it seems can cluster to find words in windo
On Wednesday, August 2, 2017 at 5:25:21 AM UTC+8, Piet van Oostrum wrote:
> Ho Yeung Lee <jobmatt...@gmail.com> writes:
>
> > which function should be used for this problem?
> >
> I think it is a kind if clustering, or a connectivity problem. There are
> special
i use number of clusters = 120
https://drive.google.com/file/d/0Bxs_ao6uuBDUZFByNVgzd0Jrdm8/view?usp=sharing
seems better, but still has a long distance to be perfect
On Friday, August 4, 2017 at 10:09:59 PM UTC+8, Ho Yeung Lee wrote:
> actually i am using python's kmeans libr
, 2017 at 8:24:54 PM UTC+8, Alain Ketterlin wrote:
> Ho Yeung Lee <jobmatt...@gmail.com> writes:
>
> > i find kmeans has to input number of cluster
> [...]
>
> https://en.wikipedia.org/wiki/Determining_the_number_of_clusters_in_a_data_set
>
> Completely off-topic
man wrote:
>
> > On 8/1/2017 2:10 PM, Piet van Oostrum wrote:
> >> Ho Yeung Lee <jobmatt...@gmail.com> writes:
> >>
> >>> def isneighborlocation(lo1, lo2):
> >>> if abs(lo1[0] - lo2[0]) < 7 and abs(lo1[1] - lo2[1]) < 7:
> >&
i find kmeans has to input number of cluster
but i do not know how many words in photo before recognization in application
of robots vision recognition
if separate high, will it become letters instead of word?
from pylab import plot,show
from numpy import vstack,array
from numpy.random import
words are splitted, I have already sorted by x[0] and x[1]
can it improver to a consecutively a few words
"檔案" <- File is succeed
but "另存新檔" failed since words are splitted
On Thursday, August 3, 2017 at 3:54:13 PM UTC+8, Ho Yeung Lee wrote:
> https://
https://gist.github.com/hoyeunglee/3d340ab4e9a3e2b7ad7307322055b550
I updated again
how to do better because some words are stored in different files
On Thursday, August 3, 2017 at 10:02:01 AM UTC+8, Ho Yeung Lee wrote:
> https://gist.github.com/hoyeunglee/f371f66d55f90dda043f7e7fea38f
discover it can not circle all words with red rectangle
and only part of words
On Wednesday, August 2, 2017 at 3:06:40 PM UTC+8, Peter Otten wrote:
> Glenn Linderman wrote:
>
> > On 8/1/2017 2:10 PM, Piet van Oostrum wrote:
> >> Ho Yeung Lee <jobmatt...@gmail.com
how to write this distance function in sort
there are the syntax error
On Wednesday, August 2, 2017 at 6:03:13 AM UTC+8, Glenn Linderman wrote:
> On 8/1/2017 2:10 PM, Piet van Oostrum wrote:
> > Ho Yeung Lee <jobmatt...@gmail.com> writes:
> >
> >> d
olocation[eachcolor] = locationsgroup
for kk in colortolocation[(0,0,0)]:
if len(colortolocation[(0,0,0)][kk]) > 7:
print kk
print colortolocation[(0,0,0)][kk]
On Wednesday, August 2, 2017 at 3:50:52 AM UTC+8, Ho Yeung Lee wrote:
> def isneighborlocation(lo1, lo2):
>
def isneighborlocation(lo1, lo2):
if abs(lo1[0] - lo2[0]) < 7 and abs(lo1[1] - lo2[1]) < 7:
return 1
elif abs(lo1[0] - lo2[0]) == 1 and lo1[1] == lo2[1]:
return 1
elif abs(lo1[1] - lo2[1]) == 1 and lo1[0] == lo2[0]:
return 1
else:
return 0
which function should be used for this problem?
On Saturday, July 29, 2017 at 11:02:30 PM UTC+8, Piet van Oostrum wrote:
> Peter Otten <__pete...@web.de> writes:
>
> > Ho Yeung Lee wrote:
> >
> >> from itertools import groupby
> >>
> >> testin
not know how to use partial and do not know what
center is.
On Tuesday, July 25, 2017 at 5:00:25 PM UTC+8, Peter Otten wrote:
> Ho Yeung Lee wrote:
>
> > from itertools import groupby
> >
> > testing1 = [(1,1),(2,3),(2,4),(3,5),(3,6),(4,6)]
> > def isneighborloca
not know how to use partial and do not know what
center is.
On Wednesday, July 26, 2017 at 2:06:08 PM UTC+8, ast wrote:
> "Ho Yeung Lee" <jobmatt...@gmail.com> a écrit dans le message de
> news:ef0bd11a-bf55-42a2-b016-d93f3b831...@googlegroups.com...
> > f
from itertools import groupby
testing1 = [(1,1),(2,3),(2,4),(3,5),(3,6),(4,6)]
def isneighborlocation(lo1, lo2):
if abs(lo1[0] - lo2[0]) == 1 or lo1[1] == lo2[1]:
return 1
elif abs(lo1[1] - lo2[1]) == 1 or lo1[0] == lo2[0]:
return 1
else:
return 0
groupda =
On Sunday, July 2, 2017 at 9:59:48 PM UTC+8, Ho Yeung Lee wrote:
> On Sunday, July 2, 2017 at 9:53:50 PM UTC+8, Ho Yeung Lee wrote:
> > On Sunday, July 2, 2017 at 9:32:36 PM UTC+8, ad...@python.org wrote:
> > > ad...@python.org:
> > > > Hi, Ho!
> > >
&
On Sunday, July 2, 2017 at 9:53:50 PM UTC+8, Ho Yeung Lee wrote:
> On Sunday, July 2, 2017 at 9:32:36 PM UTC+8, ad...@python.org wrote:
> > ad...@python.org:
> > > Hi, Ho!
> >
> >
> > it is crucial that you dump that fucking Windows of yours and become
>
On Sunday, July 2, 2017 at 9:32:36 PM UTC+8, ad...@python.org wrote:
> ad...@python.org:
> > Hi, Ho!
>
>
> it is crucial that you dump that fucking Windows of yours and become
> real pythonic under Linux !
i do not understand what is difference in result if run in window and linux
goal is to
i find parseprint function not exist in python 2.7
goal is to create a table
graph = {'A': ['B', 'C'],
'B': ['C', 'D'],
'C': ['D'],
'D': ['C'],
'E': ['F'],
'F': ['C']}
from
a = 1
b = 1
c = a + b
d = c
e = c
file =
Is there library to convert AST to DAG tree?
--
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just want to compare tuples like index (0,1), (0,2), (1,2) without duplicate
such as (2,0), (1,0) etc
On Saturday, July 1, 2017 at 7:00:17 PM UTC+8, Peter Otten wrote:
> Ho Yeung Lee wrote:
>
> > finally i searched dict.values()[index] solved this
>
> That doesn't look li
finally i searched dict.values()[index] solved this
On Saturday, July 1, 2017 at 6:00:41 PM UTC+8, Peter Otten wrote:
> Ho Yeung Lee wrote:
>
> > expect result as this first case
> >
> > ii = 0
> > jj = 0
> > for ii in range(0,3):
> > fo
jj = jj + 1
ii = ii + 1
On Saturday, July 1, 2017 at 5:05:48 PM UTC+8, Ho Yeung Lee wrote:
> sorry for typo,
>
> = 0
> = 0
> for ii in range(0,3):
> for jj in range(0,3):
> if < :
> print (ii, jj) <- corr
sorry for typo,
= 0
= 0
for ii in range(0,3):
for jj in range(0,3):
if < :
print (ii, jj) <- correct here
= + 1
= + 1
On Saturday, July 1, 2017 at 4:55:59 PM UTC+8, Ho Yeung Lee wrote:
> expect result as t
expect result as this first case
ii = 0
jj = 0
for ii in range(0,3):
for jj in range(0,3):
if ii < jj:
print (ii, jj)
but below is different
as sometimes the situation is not range(0,3), but it a a list of tuple
= 0
= 0
for ii in range(0,3):
for jj in
I find that list can not be key in dictionary
then find tuple can be as key
but when I add new tuple as key , got error in python 2.7
groupkey = {(0,0): []}
groupkey[tuple([0,3])] = groupkey[tuple([0,3])] + [[0,1]]
--
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end it and fetch the returning ack.
ackdata1=sr1(ip/data1/html1)
# Store new sequence number.
SeqNr=ackdata1.ack
# Generate RST-ACK packet
Bye=TCP(sport=80, dport=ValueOfPort, flags="FA", seq=SeqNr, ack=AckNr,
options=[('MSS', 1460)])
send(ip/Bye)
On Tuesday, June 20, 2017 at 11:36:07 P
pkts = sniff(prn=lambda x:x.sprintf("{IP:%IP.src% ->
%IP.dst%\n}{Raw:%Raw.load%\n}"), filter="tcp port 80")
for i in range(1,len(pkts)):
#if pkts[i][IP].sport == 80:
i,pkts[i][TCP].payload
i find pkts[10] do not have html source code
(8, )
(9, )
(10, )
(11, )
dir(pkts[10][TCP])
i use wb to write pubic and private key
and succeed to import private, but after decrypt, it return hex number
not a clear text
is there any more key needed?
or do wb influence the result?
from Crypto.PublicKey import RSA
keypair = RSA.generate(2048)
alice_privkey = keypair.exportKey('PEM',
lice_pubkey.txt", "r")
alice_pubkey=text_file.read()
text_file.close()
from Crypto.PublicKey import RSA
pubkey = RSA.importKey(alice_pubkey)
privkey = RSA.importKey(alice_privkey,passphrase="mysecret")
encryption_key = privkey.decrypt(alice_masterkey)
encryption
\xf0\x0e\x0c\xcb\xa8\xb1\xe7}\x90\xd3\xcfs@\xc2m\x1a^\x1b0\xa7\xdd\xcd\xea\x1f\xd5\x08\x13+y"]vu\xe3\x9e\xba\x97\x10\x90S\xea\xae1=r4Yp,\xe3\xa9\xc66H\xa7\x95[M|n\x91\x98\x9c,\xc4\xf5\x7f\x8cJ\x03\xba\x04Z0lV\xe1\xd6d\xeec@\xe1\xa0\xec\x81]\xef5\r\x12\x88\xbe/\xfc\xe01\xaacn,\x8a\xe1\x14\x8a\x
#step 1
from Crypto.PublicKey import RSA
keypair = RSA.generate(2048)
alice_privkey = keypair.exportKey('PEM', 'mysecret', pkcs=1)
#alice_privkey = keypair.exportKey()
alice_pubkey = keypair.publickey().exportKey()
text_file = open("alice_pubkey.txt", "w")
text_file.write(alice_pubkey)
line 380, in raw_decode
obj, end = self.scan_once(s, idx)
ValueError: Expecting property name: line 38 column 1 (char 871)
got another error
Chris Warrick於 2017年6月3日星期六 UTC+8下午7時20分34秒寫道：
> On 3 June 2017 at 13:00, Ho Yeung Lee <davidbenny2...@gmail.com> wrote:
> > i use
> &
i use
https://github.com/evidens/json2csv
Error:
Traceback (most recent call last):
File "json2csv.py", line 148, in
loader.load(args.json_file)
File "json2csv.py", line 53, in load
self.process_each(json.load(json_file))
File "C:\Python27\lib\json\__init__.py", line 291, in load
if keep module1.py code together with mainmodule1.exe, how to convert to
executable file with py2exe in this case?
after tried, it can run executable file with source code module1.py
but the modified date can not be changed even if content of module1.py changed
then i delete the file and change
On Sunday, May 21, 2017 at 2:47:26 PM UTC+8, Ho Yeung Lee wrote:
> On Sunday, May 21, 2017 at 2:40:49 PM UTC+8, top...@googlemail.com wrote:
> > Did you call freeze_support() function after script start?
> > https://docs.python.org/3/library/multiprocessing.html#multiprocessing
On Sunday, May 21, 2017 at 2:40:49 PM UTC+8, top...@googlemail.com wrote:
> Did you call freeze_support() function after script start?
> https://docs.python.org/3/library/multiprocessing.html#multiprocessing.freeze_support
no, i did not call freeze_support()
--
i use window subsystem ubuntu
and install python 3 and tensorflow
then when try deep learning
https://www.tensorflow.org/tutorials/wide_and_deep
got error when urlretrieve local directory in ubuntu in window
tried urllib3 still have error
import tempfile
import pandas as pd
import urllib as
i mean executable file can not run the multiprocessing thread
after convert to executable file with py2exe
On Sunday, May 21, 2017 at 2:09:04 PM UTC+8, Ho Yeung Lee wrote:
> p = multiprocessing.Process(target=helloconnect, args=(host,"",))
>
> multiprocessing.Process can
p = multiprocessing.Process(target=helloconnect, args=(host,"",))
multiprocessing.Process can not start a thread in py2exe
it can compile and run without error
but it can not run function helloconnect
--
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On Saturday, April 15, 2017 at 3:18:58 PM UTC+8, Peter Otten wrote:
> Ho Yeung Lee wrote:
>
> > Python 2.7.6 (default, Jun 22 2015, 18:00:18)
> > [GCC 4.8.2] on linux2
> > Type "help", "copyright", "credits" or "license" for more inf
Python 2.7.6 (default, Jun 22 2015, 18:00:18)
[GCC 4.8.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import ssl
Traceback (most recent call last):
File "", line 1, in
File "/home/martin/Documents/ssl.py", line 13, in
SSLError -- exception raised
http://construct.readthedocs.io/en/latest/basics.html
format.build can build the hex string,
but after edit attribute of the format parse result
it is a container, how to convert this container back to format build result?
aaa = ["a","ab","c","b","bc"]
def similar(aa):
similarset = []
for ii in range(0,len(aa)):
for jj in range(ii,len(aa)):
if ii <> jj:
print("("+str(ii)+","+str(jj)+")")
if (aa[ii] in aa[jj]) or (aa[jj] in aa[ii]):
On Sunday, March 26, 2017 at 7:40:20 PM UTC+8, Ho Yeung Lee wrote:
> On Sunday, March 26, 2017 at 7:32:12 PM UTC+8, Ho Yeung Lee wrote:
> > On Sunday, March 26, 2017 at 10:33:51 AM UTC+8, Deborah Swanson wrote:
> > > Someone here can probably help you, but they'll need your Py
On Sunday, March 26, 2017 at 7:32:12 PM UTC+8, Ho Yeung Lee wrote:
> On Sunday, March 26, 2017 at 10:33:51 AM UTC+8, Deborah Swanson wrote:
> > Someone here can probably help you, but they'll need your Python
> > version, operating system, and full traceback. They get tired o
what went wrong and
> when (after which statements).
>
>
> Ho Yeung Lee wrote, on Saturday, March 25, 2017 1:38 AM
> >
> > expect below to run forever and keep running a fixed number
> > of thread in python
> >
> > would like to kill tasks when process connect i
TCP127.0.0.1:1663 127.0.0.1:28091ESTABLISHED 9900
TCP127.0.0.1:28091127.0.0.1:1663 ESTABLISHED 9532
above two process connect to itself, named ismagent and updateui.exe
are they the malware software?
TCP127.0.0.1:1663
expect below to run forever and keep running a fixed number of thread in python
would like to kill tasks when process connect internet except chrome
and explorer.exe
i do this because MalwareBytes can not disconnect these existing trojan when my
notebook connect internet
after run a few
toweb.mp4" -into %d -geometry 100x200 -sb &' %
wid)
root.mainloop()
On Thursday, March 16, 2017 at 1:16:41 PM UTC+8, Ho Yeung Lee wrote:
> martin@ubuntu:~/Downloads/python-vlc/examples$ xdg-screensaver: Window
> 0x0900 does not exist
>
> error when run after inherit
uot;tkinter vlc").grid(row=r,column=c)
#os.system('xterm -into %d -geometry 40x20 -sb &' % wid)
#os.system('vlc --no-fullscreen
"file:///home/martin/Downloads/autoweb.mp4" -into %d -geometry 100x200 -sb &' %
wid)
root.mainloop()
On Thursday, March 16, 2017 at
we have many TV that would like to be monitored,
how to embed non-tkinter VLC player into grid of tkinter with python?
below code can embeded xterm but not for VLC player
import vlc
from Tkinter import *
import os
root = Tk()
for r in range(2):
for c in range(1):
termf =
before cloususerlogin
Unexpected error:
after map pool
...
passwordlist = pickle.load( open( str(currentworkingdirectory) +
"\\decryptedsecret.p", "rb" ) )
def processInput(host):
try:
decrypt_file(sys.argv[1], str(currentworkingdirectory) +
"\\encryptedsecret.p",
Is "two different input map to one unique target called nonlinear case " or
"one unique input map to two different target called nonlinear case"? Which
learning method can train these two cases or no method to train one of case?
--
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Must target be only one bit one such as 0001,0010,0100,1000 In supervised
neural learning f(w*p+b) with perceptron rule w = w + e for linear case?
with neural network design
does it means that can not use two or more one as target such as
0011,0110,1100,1010, 0111,1110,1101, etc when training
how to override the solver function in sympy?
--
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y, December 2, 2016 at 1:02:19 PM UTC+8, Steve D'Aprano wrote:
> On Fri, 2 Dec 2016 01:35 pm, Ho Yeung Lee wrote:
>
> > from __future__ import division
> > import ast
> > from sympy import *
> > x, y, z, t = symbols('x y z t')
> > k, m, n = symbols('k m n', in
cember 1, 2016 at 7:19:58 PM UTC+8, Steve D'Aprano wrote:
> On Thu, 1 Dec 2016 05:26 pm, Ho Yeung Lee wrote:
>
> > import ast
> > from __future__ import division
>
> That's not actually your code. That will be a SyntaxError.
>
> Except in the interactive interpreter,
import ast
from __future__ import division
from sympy import *
x, y, z, t = symbols('x y z t')
k, m, n = symbols('k m n', integer=True)
f, g, h = symbols('f g h', cls=Function)
import inspect
class A:
@staticmethod
def __additionFunction__(a1, a2):
return a1*a2 #Put what
can this graph library handle recursive function call this symbol
If it recursive call a function 3 times then in the inner loop call another
function , can this graph library
Show this relationship
I find video that viv can show this program flow.
--
I updated the code in msdn forum,
I calculated from the end of file
Discover file 4550 takes a long time to run,
Assume it runs a whole day a file, 4550 days I guess need 12 years to finish
full combination if only run at home.
Hope Python sympy can be faster than cmaple in Amazon instance
Sorry my calculation is wrong, it should have around 14 billions of
combinations after using program to count.
--
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https://social.msdn.microsoft.com/Forums/vstudio/en-US/5f0a9a51-a256-4671-a5fc-e213949e7204/how-to-refactor-3-nested-for-loop-into-smaller-for-loop-assume-each-of-them-independent?forum=csharpgeneral
I wrote a algorithm to split for loop to generate maplesoft code for limited
memory
Assume I
i saved a list of matrix of algebra into .m file in maple
How to read and import into Python for sympy to use?
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i do not understand,
how to solve this frozonset ?
Lawrence D’Oliveiro於 2016年10月5日星期三 UTC+8下午2時24分13秒寫道：
> On Wednesday, October 5, 2016 at 2:35:25 PM UTC+13, meInvent bbird wrote:
> > it return unhashable type 'set'
>
> This is what “frozenset” is for--it’s the immutable counterpart of
what is the command or code to write to use virtual memory if i use extra
20 GB from hard disk as memory, means from 70GB memory to 90GB memory
and left 10GB for file?
Michael Torrie於 2016年6月25日星期六 UTC+8上午11時00分36秒寫道：
> On 06/24/2016 08:44 PM, Dennis Lee Bieber wrote:
> > I don't know how
path = []
mresult = DFS(b, 2, 2, mylist, path)
Michael Selik於 2016年6月10日星期五 UTC+8上午6時45分14秒寫道：
> I like using Yelp's mrjob module (https://github.com/Yelp/mrjob) to run
> Python on Hadoop.
>
> On Thu, Jun 9, 2016 at 2:56 AM Ho Yeung Lee <davidbenny2...@gmail.com>
> wrote
i write a program, it is like forever loop
but i only restrict it to run 2 level recursively,
why it is slow, where is the problem?
M1 = {}
M2 = {}
M3 = {}
M4 = {}
M5 = {}
V6 = {}
M1['00']=0
M1['01']=1
M1['02']=1
M1['10']=2
M1['11']=2
M1['12']=1
M1['20']=1
M1['21']=2
M1['22']=1
M2['00']=0
i got M1 to M5 and V6 operator
and would like to do a full combination and result will also act among each
other,
map reduce attract my application
how to use this in this example?
actually below is like vlookup
then example is op3(op2(op1(x->y, y->z)), x->z)
search which combinations will
in the following code, node 3 and node 4 running parallel
if there are 100 nodes running parallel, how can they notify each other
i find this post stackoverflow,
http://stackoverflow.com/questions/29324346/how-do-i-connect-asyncio-coroutines-that-continually-produce-and-consume-data
if
Peter Otten於 2016年2月21日星期日 UTC+8下午10時07分18秒寫道：
> davidbenny2...@gmail.com wrote:
>
> > File "mainpy.py", line 81
> > for functionlistelement in functionlist0
> >^
> > SyntaxError: invalid syntax
> >
> >
> > import asyncio
>
> [snip]
>
> >
Hi Chris,
0 ---> 2 --> 3--> 1 ---> 0
---> 4 /
i am practicing task flow in this graph situation
when current state is 2 , there are 3 and 4 to run parallel and wait list of
tasks finish before running to 1 ,
however i feel that my code has been wrong because 3 and 4 can not combine
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