re.sub question (regular expressions)
What does this line do?... input_ = re.sub(([a-zA-Z]+), '\\1', input_) Does it remove parentheses from words? e.g. (foo) - foo ??? I'd like to replace [a-zA-Z] with \w but \w makes it blow up. In other words, re.sub((\w+), '\\1', input_) blows up. Why? cs -- http://mail.python.org/mailman/listinfo/python-list
Re: re.sub question (regular expressions)
Chris Seberino wrote: What does this line do?... input_ = re.sub(([a-zA-Z]+), '\\1', input_) Does it remove parentheses from words? e.g. (foo) - foo ??? I'd like to replace [a-zA-Z] with \w but \w makes it blow up. In other words, re.sub((\w+), '\\1', input_) blows up. Why? cs ( has a special meaning of not preceded by \ (see re help) the first line transform 'foo' into 'foo' your solution is doing the same. If I'm wrong, MRAB will come into rescue anyway :o) JM -- http://mail.python.org/mailman/listinfo/python-list
Re: re.sub question (regular expressions)
Chris Seberino wrote: What does this line do?... input_ = re.sub(([a-zA-Z]+), '\\1', input_) Why don't you try it? Does it remove parentheses from words? e.g. (foo) - foo ??? No, it puts quotes around them. I'd like to replace [a-zA-Z] with \w but \w makes it blow up. In other words, re.sub((\w+), '\\1', input_) blows up. Why? What do you mean blow up? It worked for me in Python v2.6.2. -- http://mail.python.org/mailman/listinfo/python-list
