Say I have module foo.py:
def a(x):
def b():
x
del x
If I run foo.py under Python 2.4.4 I get:
File foo.py, line 4
del x
SyntaxError: can not delete variable 'x' referenced in nested
scope
Under Python
On Tue, 9 Dec 2008 at 13:11, Albert Hopkins wrote:
Say I have module foo.py:
def a(x):
def b():
x
del x
[...]
The difference is under Python 2.4 I get a traceback with the lineno and
offending line, but I do not get a traceback in Pythons 2.6 and 3.0.
On Tue, 09 Dec 2008 13:11:40 -0500, Albert Hopkins wrote:
The difference is under Python 2.4 I get a traceback with the lineno and
offending line, but I do not get a traceback in Pythons 2.6 and 3.0.
If tracebacks are broken, surely that would be a pretty huge bug. It
seems to be broken in
On Tue, 2008-12-09 at 22:57 +, Steven D'Aprano wrote:
[...]
So is there a way to find the offending code w/o having to go
through
every line of code in 'foo' by hand?
Just search for del x in your code. Your editor does have a search
function, surely?
Well, you'd think I'd be
On Tue, 09 Dec 2008 22:57:36 -0500, Albert Hopkins wrote:
On Tue, 2008-12-09 at 22:57 +, Steven D'Aprano wrote: [...]
So is there a way to find the offending code w/o having to go
through
every line of code in 'foo' by hand?
Just search for del x in your code. Your editor does have a
