On 20 Nov, 06:01, srinivasan srinivas [EMAIL PROTECTED] wrote:
Yes it works for most of the cases. But it doesn't for the following case:
str(abs(int(1234567.89)-1234567.89))
'0.88999898'
Well, that is 0.89 or about as near to it as the calculation can
represent. Like other numbers
Thanks,
Srini
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On Wed, Nov 19, 2008 at 8:35 AM, srinivasan srinivas
[EMAIL PROTECTED] wrote:
Thanks,
Srini
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x = 2.99340584
y = abs(int(x) - x)
y
0.99340584
On Nov 20, 12:35 am, srinivasan srinivas [EMAIL PROTECTED]
wrote:
null
| import math
| num = 123.4567
| math.modf(num)
| (0.456699789, 123.0)
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, 2008 7:14:17 PM
Subject: Re: Getting fractional part from a float without using string
operations
On Wed, Nov 19, 2008 at 8:35 AM, srinivasan srinivas [EMAIL PROTECTED] wrote:
Thanks,
Srini
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On Nov 19, 1:44 pm, John Machin [EMAIL PROTECTED] wrote:
On Nov 20, 12:35 am, srinivasan srinivas [EMAIL PROTECTED]
wrote:
null
| import math
| num = 123.4567
| math.modf(num)
| (0.456699789, 123.0)
def frac(n):
return n - int(n)
--
srinivasan srinivas wrote:
Yes. But it didn't give only the expected decimals.
For ex:
a = 1.23
abs(int(a) -a)
0.22998
I would like to get the result '0.23' only.
well, thats what get stored internally - there
is no way around it if you are using floating
point numbers:
MRAB [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Nov 19, 1:44 pm, John Machin [EMAIL PROTECTED] wrote:
On Nov 20, 12:35 am, srinivasan srinivas [EMAIL PROTECTED]
wrote:
null
| import math
| num = 123.4567
| math.modf(num)
| (0.456699789, 123.0)
def frac(n):
On Nov 20, 3:38 am, Blind Anagram [EMAIL PROTECTED] wrote:
MRAB [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Nov 19, 1:44 pm, John Machin [EMAIL PROTECTED] wrote:
On Nov 20, 12:35 am, srinivasan srinivas [EMAIL PROTECTED]
wrote:
null
| import math
| num = 123.4567
]; python-list@python.org
Sent: Wednesday, 19 November, 2008 7:33:46 PM
Subject: Re: Getting fractional part from a float without using string
operations
srinivasan srinivas wrote:
Yes. But it didn't give only the expected decimals.
For ex:
a = 1.23
abs(int(a) -a)
0.22998
I
]; python-list@python.org
Sent: Wednesday, 19 November, 2008 7:33:46 PM
Subject: Re: Getting fractional part from a float without using string
operations
srinivasan srinivas wrote:
Yes. But it didn't give only the expected decimals.
For ex:
a = 1.23
abs(int(a) -a)
0.22998
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