Re: How to create a script that list itself ?

[Tim Roberts]

Duncan Booth [EMAIL PROTECTED] wrote:

Dave Hansen wrote:

 Stealing from the old C chestnut:
 
 s=s=%c%s%c;print s%%(34,s,34);print s%(34,s,34)

Or a bit shorter:

s='s=%s;print s%%`s`';print s%`s`

It was pointed out to me that the shortest Python program which produces
itself on stdout is:
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Re: How to create a script that list itself ?

[Mike Meyer]

Tim Roberts [EMAIL PROTECTED] writes:
 It was pointed out to me that the shortest Python program which produces
 itself on stdout is:
 -- 

Which, oddly enough, is also the shortest shell program that produces
itself on stdout.

   mike
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Re: How to create a script that list itself ?

[Duncan Booth]

Dave Hansen wrote:

 Stealing from the old C chestnut:
 
 s=s=%c%s%c;print s%%(34,s,34);print s%(34,s,34)

Or a bit shorter:

s='s=%s;print s%%`s`';print s%`s`
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How to create a script that list itself ?

[Patrick Allaire]

How to create a script that list itself ?

I would like to know, where is the script's code is stored once we
start it. I know I can achieve that, using files :

print file('myscript.py','rb').read()

But is there a way / a variable that contains the current file in
memory ?

Thanks.

Xaqc

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Re: How to create a script that list itself ?

[Dave Hansen]

On 9 Jan 2006 10:09:19 -0800 in comp.lang.python, Patrick  Allaire
[EMAIL PROTECTED] wrote:

How to create a script that list itself ?

Stealing from the old C chestnut:

s=s=%c%s%c;print s%%(34,s,34);print s%(34,s,34)



I would like to know, where is the script's code is stored once we
start it. I know I can achieve that, using files :

Well, in the above, the script (or rather, the information necessary
to print the script) is actually stored in a string that is part of
the script...

Regards,
-=Dave

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Re: How to create a script that list itself ?

[Grant Edwards]

On 2006-01-09, Patrick  Allaire [EMAIL PROTECTED] wrote:

 How to create a script that list itself ?

This is probably about as close as you're going to get:

  import sys
  pring open(sys.argv[0],'r').read()

And that isn't 100% reliable.
  
 I would like to know, where is the script's code is stored once we
 start it.

It isn't.  At least none of the implimentations I know of have
the script's source code in memory.  The PVM or JVM bytecodes
to which the program has been compiled are in memory somewhere,
and there _may_ be some trick you can use to get at those.

 I know I can achieve that, using files :

 print file('myscript.py','rb').read()

 But is there a way / a variable that contains the current file in
 memory ?

I don't believe so.

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Re: How to create a script that list itself ?

[Szabolcs Nagy]

 But is there a way / a variable that contains the current file in
 memory ?
yes: import __main__

you can do:

import inspect
import __main__
print inspect.getsource(__main__)

or simply:

print open(__file__).read()


nsz

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Re: How to create a script that list itself ?

[[EMAIL PROTECTED]]

import sys

path = os.path.dirname(sys.argv[0])
print Path:%s % (path)



##

If you ran this as a script,
This would print the location of where the script itself is running.



Hope it helps!

Rob

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