On 3 Oct 2006 19:09:53 -0700, SpreadTooThin [EMAIL PROTECTED] wrote:
If you are deriving a new class from another class,
that you must (I assume) know the initializer of the other class.
So in myClass
import array
class myClass(arrary.array):
def __init__(self, now here I need to put
SpreadTooThin wrote:
If you are deriving a new class from another class,
that you must (I assume) know the initializer of the other class.
So in myClass
import array
class myClass(arrary.array):
def __init__(self, now here I need to put array's constructor
parameters..., then mine):
Peter Otten wrote:
SpreadTooThin wrote:
If you are deriving a new class from another class,
that you must (I assume) know the initializer of the other class.
So in myClass
import array
class myClass(arrary.array):
def __init__(self, now here I need to put array's constructor
SpreadTooThin wrote:
the =() syntax indicates what?
No special syntax, just an empty tuple as a default parameter.
In this case I could have used an empty list, too, but I thought I'd spare
you the dangers of mutable default values as explained here:
http://www.python.org/doc/faq/general/#id53
If you are deriving a new class from another class,
that you must (I assume) know the initializer of the other class.
So in myClass
import array
class myClass(arrary.array):
def __init__(self, now here I need to put array's constructor
parameters..., then mine):
SpreadTooThin wrote:
If you are deriving a new class from another class,
that you must (I assume) know the initializer of the other class.
So in myClass
import array
class myClass(arrary.array):
def __init__(self, now here I need to put array's constructor
parameters..., then mine):
