Hello everyone. I think it is related to the precision with double
arithmetic so i posted here.I am trying with this problem (https://
www.spoj.pl/problems/CALCULAT) and the problem say that Note : for
all test cases whose N=100, its K=15. I know precision of doubles
in c is 16 digits. Could some
On Feb 20, 11:17 am, mukesh tiwari mukeshtiwari.ii...@gmail.com
wrote:
Hello everyone. I think it is related to the precision with double
arithmetic so i posted here.I am trying with this problem
(https://www.spoj.pl/problems/CALCULAT) and the problem say that Note : for
all test cases whose
A quick solution I came out with, no stirling numbers and had tried to avoid
large integer multiplication as much as possible.
import math
for i in range(int(raw_input())):
n, k, l = [int(i) for i in raw_input().split()]
e = sum(math.log10(i) for i in range(1, n+1))
frac_e = e -
On Feb 20, 5:44 pm, Mark Dickinson dicki...@gmail.com wrote:
On Feb 20, 11:17 am, mukesh tiwari mukeshtiwari.ii...@gmail.com
wrote:
Hello everyone. I think it is related to the precision with double
arithmetic so i posted here.I am trying with this problem
On Feb 20, 8:13 pm, mukesh tiwari mukeshtiwari.ii...@gmail.com
wrote:
On Feb 20, 5:44 pm, Mark Dickinson dicki...@gmail.com wrote:
On Feb 20, 11:17 am, mukesh tiwari mukeshtiwari.ii...@gmail.com
wrote:
Hello everyone. I think it is related to the precision with double
arithmetic
I don't know if is possible to import this decimal module but kindly
tell me.Also a bit about log implementation
Why don't you read about decimal module (there is log too in it) and try
writing your approach here in case it does not work? Or you insist someone
to rewrite your code using decimal
On Feb 20, 3:37 pm, mukesh tiwari mukeshtiwari.ii...@gmail.com
wrote:
I don't know if is possible to import this decimal module but kindly
tell me.Also a bit about log implementation
The decimal module is part of the standard library; I don't know what
the rules are for SPOJ, but you're
On Sat, Feb 20, 2010 at 2:42 PM, Shashwat Anand
anand.shash...@gmail.com wrote:
A quick solution I came out with, no stirling numbers and had tried to avoid
large integer multiplication as much as possible.
import math
for i in range(int(raw_input())):
n, k, l = [int(i) for i in
@Mark,
The str(...).split('.') here doesn't do a good job of extracting the
integer part when its argument is = 1e12, since Python produces a
result in scientific notation. I think you're going to get strange
results when k = 13.
Yeah, you were correct. I tested it for k = 13, and there
