Re: Syncing up iterators with gaps

On Thu, 29 Sep 2016 11:38 am, Tim Chase wrote: > This seems to discard the data's origin (data1/data2/data3) which is > how I determine whether to use process_a(), process_b(), or > process_c() in my original example where N iterators were returned, > one for each input iterator. So add another

Re: Syncing up iterators with gaps

On 2016-09-29 10:20, Steve D'Aprano wrote: > On Thu, 29 Sep 2016 05:10 am, Tim Chase wrote: > > data1 = [ # key, data1 > > (1, "one A"), > > (1, "one B"), > > (2, "two"), > > (5, "five"), > > ] > > So data1 has keys 1, 1, 2, 5. > Likewise data2 has keys 1, 2, 3, 3, 3, 4 and

Re: Syncing up iterators with gaps

On Thu, 29 Sep 2016 05:10 am, Tim Chase wrote: > I've got several iterators sharing a common key in the same order and > would like to iterate over them in parallel, operating on all items > with the same key. I've simplified the data a bit here, but it would > be something like > > data1 = [

Re: Syncing up iterators with gaps

Tim Chase wrote: > I've got several iterators sharing a common key in the same order and > would like to iterate over them in parallel, operating on all items > with the same key. I've simplified the data a bit here, but it would > be something like > > data1 = [ # key, data1 > (1, "one

Re: Syncing up iterators with gaps

Here is a slight variation of Chris A's code that does not require more than a single look-ahead per generator. It may be better depending on the exact data passed in. Chris A's version will store all of the items for each output that have a matching key, which, depending on the expected data,

Re: Syncing up iterators with gaps

On Thu, Sep 29, 2016 at 5:10 AM, Tim Chase wrote: > And I'd like to do something like > > for common_key, d1, d2, d3 in magic_happens_here(data1, data2, data3): > for row in d1: > process_a(common_key, row) > for thing in d2: >

Re: Syncing up iterators with gaps

On 9/28/2016 3:10 PM, Tim Chase wrote: I've got several iterators sharing a common key in the same order and would like to iterate over them in parallel, operating on all items with the same key. I've simplified the data a bit here, but it would be something like data1 = [ # key, data1

Syncing up iterators with gaps

I've got several iterators sharing a common key in the same order and would like to iterate over them in parallel, operating on all items with the same key. I've simplified the data a bit here, but it would be something like data1 = [ # key, data1 (1, "one A"), (1, "one B"), (2,