Re: accessing superclass methods from subclass

2010-05-12 Thread Bruno Desthuilliers
Chris Rebert a écrit : (snip) Here is how I would rewrite your example: class Shape(object): def __init__(self, x=0, y=0): self.x = x self.y = y @property def location(self): return (self.x, self.y) @location.setter def location(self, val):

Re: accessing superclass methods from subclass

2010-05-10 Thread Jean-Michel Pichavant
ben wrote: Ok, thanks for the info. What would be a better way to do this? What I'm trying to do is treat things in a reasonable OOP manner (all fairly new to me, esp. in Python). Here's a made-up example with a little more context. Let's say you're making a drawing program that can draw

Re: accessing superclass methods from subclass

2010-05-09 Thread TFH
On Sat, 08 May 2010 16:50:11 -0700, ben wrote: Why doesn't this work: class C1: def f1(self): print(f1) class C2(C1): f1() It throws this error: Traceback (most recent call last): File ./c1.py, line 7, in module class C2(C1): File ./c1.py, line 8, in

Re: accessing superclass methods from subclass

2010-05-09 Thread Lie Ryan
On 05/09/10 10:05, Chris Rebert wrote: Additionally, it makes no sense to call an *instance* method such as f1() in a class context. Or in Java-speak: you can't call a non-static method in a static context. nitActually, in python it does make sense, with a caveat that you have to provide the

accessing superclass methods from subclass

2010-05-08 Thread ben
Why doesn't this work: class C1: def f1(self): print(f1) class C2(C1): f1() It throws this error: Traceback (most recent call last): File ./c1.py, line 7, in module class C2(C1): File ./c1.py, line 8, in C2 f1() NameError: name 'f1' is not defined f1() is an

Re: accessing superclass methods from subclass

2010-05-08 Thread Chris Rebert
On Sat, May 8, 2010 at 4:50 PM, ben thomasstr...@gmail.com wrote: Why doesn't this work: class C1:    def f1(self):        print(f1) class C2(C1):    f1() It throws this error: Traceback (most recent call last):  File ./c1.py, line 7, in module    class C2(C1):  File ./c1.py, line

Re: accessing superclass methods from subclass

2010-05-08 Thread MRAB
ben wrote: Why doesn't this work: class C1: def f1(self): print(f1) class C2(C1): f1() It throws this error: Traceback (most recent call last): File ./c1.py, line 7, in module class C2(C1): File ./c1.py, line 8, in C2 f1() NameError: name 'f1' is not defined

Re: accessing superclass methods from subclass

2010-05-08 Thread ben
Ok, thanks for the info. What would be a better way to do this? What I'm trying to do is treat things in a reasonable OOP manner (all fairly new to me, esp. in Python). Here's a made-up example with a little more context. Let's say you're making a drawing program that can draw various shapes.

Re: accessing superclass methods from subclass

2010-05-08 Thread Chris Rebert
On May 8, 7:05 pm, Chris Rebert c...@rebertia.com wrote: On Sat, May 8, 2010 at 4:50 PM, ben thomasstr...@gmail.com wrote: Why doesn't this work: class C1:    def f1(self):        print(f1) class C2(C1):    f1() It throws this error: Traceback (most recent call last):  File