dictionary that have functions with arguments

hi i have a dictionary defined as execfunc = { 'key1' : func1 } to call func1, i simply have to write execfunc[key1] . but if i have several arguments to func1 , like execfunc = { 'key1' : func1(**args) } how can i execute func1 with variable args? using eval or exec? thanks --

Re: dictionary that have functions with arguments

[EMAIL PROTECTED] wrote: hi i have a dictionary defined as execfunc = { 'key1' : func1 } to call func1, i simply have to write execfunc[key1] . No, you ALSO have to write ( ) [[parentheses]] after that. MENTIONING a function doesn't call it, it's the parentheses that do it. but if i

Re: dictionary that have functions with arguments

[EMAIL PROTECTED] wrote: hi i have a dictionary defined as execfunc = { 'key1' : func1 } to call func1, i simply have to write execfunc[key1] . but if i have several arguments to func1 , like execfunc = { 'key1' : func1(**args) } how can i execute func1 with variable args? using

Re: dictionary that have functions with arguments

[EMAIL PROTECTED] writes: hi i have a dictionary defined as execfunc = { 'key1' : func1 } to call func1, i simply have to write execfunc[key1] . but if i have several arguments to func1 , like execfunc = { 'key1' : func1(**args) } how can i execute func1 with variable args? using eval

Re: dictionary that have functions with arguments

Ron Adam wrote: Eval or exec aren't needed. Normally you would just do... execfunc['key1'](**args) If your arguments are stored ahead of time with your function... Committed revision 41366. You could then do... func, args = execfunc['key1'] func(**args) Interesting

Re: dictionary that have functions with arguments

Alex Martelli wrote: execfunc = { 'key1' : (func1, ()), 'key2' : (func2, args) } now, something like: f, a = execfunc[k] f(**a) will work for either key. Shouldn't func1's args be a dictionary, not a tuple? -- http://mail.python.org/mailman/listinfo/python-list

Re: dictionary that have functions with arguments

Neal Norwitz wrote: Ron Adam wrote: Eval or exec aren't needed. Normally you would just do... execfunc['key1'](**args) If your arguments are stored ahead of time with your function... Committed revision 41366. Committed revision 41366 ? You could then do... func, args =

Re: dictionary that have functions with arguments

Leif K-Brooks [EMAIL PROTECTED] wrote: Alex Martelli wrote: execfunc = { 'key1' : (func1, ()), 'key2' : (func2, args) } now, something like: f, a = execfunc[k] f(**a) will work for either key. Shouldn't func1's args be a dictionary, not a tuple? Yes,

Re: dictionary that have functions with arguments

On 1 Nov 2005 20:02:41 -0800, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: hi i have a dictionary defined as execfunc = { 'key1' : func1 } ## def __HELLO(x=' '): print 'HELLO',x def __BYE(x=' '): print 'BYE',x def __PRINT(x=None, y=None): print 'PRINT',x,y cmds =