explain slice assignment to newb

2008-09-20 Thread Andrew
please explain this behavior to a newb: a = [1,2,3,4] b = [a,b,c,d] a [1, 2, 3, 4] b ['a', 'b', 'c', 'd'] a[0:2] [1, 2] a [1, 2, 3, 4] b[2:4] ['c', 'd'] a[0:2] = b[0:2] b[2:4] = a[2:4] a ['a', 'b', 3, 4] b ['a', 'b', 3, 4] -- http://mail.python.org/mailman/listinfo/python-list

Re: explain slice assignment to newb

2008-09-20 Thread Sean DiZazzo
On Sep 20, 2:20 pm, Andrew [EMAIL PROTECTED] wrote: please explain this behavior to a newb: a = [1,2,3,4] b = [a,b,c,d] a [1, 2, 3, 4] b ['a', 'b', 'c', 'd'] a[0:2] [1, 2] a [1, 2, 3, 4] b[2:4] ['c', 'd'] a[0:2] = b[0:2] b[2:4] = a[2:4] a ['a', 'b', 3, 4] b ['a',

Re: explain slice assignment to newb

2008-09-20 Thread Terry Reedy
Andrew wrote: please explain this behavior to a newb: Read the section on sequence slicing in the Library Reference. Use the interactive interpreter or IDLE to perform experiments, like you did, until you understand to your satisfaction. --

Re: explain slice assignment to newb

2008-09-20 Thread Stephen Horne
On Sat, 20 Sep 2008 14:20:20 -0700 (PDT), Andrew [EMAIL PROTECTED] wrote: please explain this behavior to a newb: a = [1,2,3,4] b = [a,b,c,d] a[0:2] = b[0:2] The slice [0:2] represent positions 0 = x 2 Replaces the [1, 2] from [1, 2, 3, 4] with ['a', 'b'] Result: a = ['a', 'b', 3, 4]