Re: force URLencoding script
On Jan 15, 4:46 pm, r0g wrote:
> João wrote:
> > On Jan 15, 2:38 pm, r0g wrote:
> >> João wrote:
> >>> On Jan 14, 5:58 pm, r0g wrote:
> João wrote:
> > On Jan 12, 10:07 pm, r0g wrote:
> >> João wrote:
> > for the following data,
> > authentication = "UID=somestring&"
> > message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
> > Succ. : 94.47%'
> > dest_number = 'XXX'
> > url_values = urlencode({'M':message})
> > enc_data = authentication + url_values + dest_number
> > I'm getting null for
> > full_url = Request(url, enc_data, headers)
> > and thus,
> > response = urlopen(full_url).read()
> > returns,
> > TypeError:
> > )
> Are you sure it's returning a null and not just some other unexpected
> type?
> I think your problem may be that you are passing a urllib2 class to
> urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
> import urllib2
> request_object = urllib2.Request('http://www.example.com')
> response = urllib2.urlopen(request_object)
> the_page = response.read()
> Roger.
> >>> Thanks Roger.
> >>> I think it's a null because i did a print(full_url) right after the
> >>> Request
> >>> I tried
> >>> request_object = urllib2.Request('http://www.example.com')
> >>> print(request_object)
> >>> but when printing I get:
> >> Hi João,
>
> >> That's exactly what you want, an object that is an instance of the
> >> Request class. That object doesn't do anything by itself, you still need
> >> to a) Connect to the server and request that URL and b) Read the data
> >> from the server.
>
> >> a) To connect to the web server and initialize the request you need to
> >> call urllib2.urlopen() with the Request object you just created and
> >> assign the result to a name e.g.
>
> response = urllib2.urlopen(request_object)
> >> That will give you an object (response) that you can call the .read()
> >> method of to get the web page data.
>
> the_page = response.read()
> >> If that doesn't make sense or seem to work for you then please try
> >> reading the following website from top to bottom before taking any
> >> further steps...
>
> >>http://www.voidspace.org.uk/python/articles/urllib2.shtml
>
> >>> I've read about Python 2.4 not playing well with proxies even with no
> >>> proxy activated.
> >>> Any sugestion?
> >> I doubt any language can play well with proxies if there are none so I
> >> doubt it's a factor ;)
>
> >> Good luck,
>
> >> Roger.
>
> > lol.
> > I've expressed myself poorly,
> > I meant I read about some issues when getting the Request + urlopen
> > working when there's a proxy involved (like in my case)
> > even when activating a no_proxy configuration, something like,
>
> > proxy_support = urllib.ProxyHandler({})
> > opener = urllib.build_opener(proxy_support)
> > urllib.install_opener(opener)
>
> > But I don't know how to use it :(
>
> That is how you use it IIRC, this installs the proxy handler into urllib
> and subsequent objects you subclass from urllib will use the custom handler.
>
> From what I can tell, you should be using urllib2 though, not urllib.
>
> Lets take a step back. You had the following line...
>
> request_object = urllib2.Request('http://www.example.com')
>
> ...You printed it and it showed that you had created a Request object
> right. Now what happens when you type...
>
> response = urllib2.urlopen(request_object)
> print response
>
> ?
>
> Roger.
Thanks for the patience Roger.
Your explanation opened my eyes.
I finally got it to work, and it turned out I didn't have to include
any custom proxy handler to avoid our proxy.
It ended on such a small and simple block of code after getting the
pieces together..
#!/usr/bin/env python
import sys
from urllib2 import Request, urlopen
from urllib import urlencode
authentication = "UID=124675&PW=gdberishyb8LcIANtvT89QVQ==&"
url = 'http://10.112.28.221:38080/GwHTTPin/sendtext'
encoded_data = urlencode({'M':sys.argv[2],
'N':sys.argv[1]})
# Was having problem with this one, shouldn't have tried to pass the
authentication as an urlencode parameter because it was breaking the
password string!
sent_data = authentication + encoded_data
full_url = Request(url,sent_data)
response = urlopen(full_url).read()
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
On Jan 15, 4:46 pm, r0g wrote:
> João wrote:
> > On Jan 15, 2:38 pm, r0g wrote:
> >> João wrote:
> >>> On Jan 14, 5:58 pm, r0g wrote:
> João wrote:
> > On Jan 12, 10:07 pm, r0g wrote:
> >> João wrote:
> > for the following data,
> > authentication = "UID=somestring&"
> > message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
> > Succ. : 94.47%'
> > dest_number = 'XXX'
> > url_values = urlencode({'M':message})
> > enc_data = authentication + url_values + dest_number
> > I'm getting null for
> > full_url = Request(url, enc_data, headers)
> > and thus,
> > response = urlopen(full_url).read()
> > returns,
> > TypeError:
> > )
> Are you sure it's returning a null and not just some other unexpected
> type?
> I think your problem may be that you are passing a urllib2 class to
> urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
> import urllib2
> request_object = urllib2.Request('http://www.example.com')
> response = urllib2.urlopen(request_object)
> the_page = response.read()
> Roger.
> >>> Thanks Roger.
> >>> I think it's a null because i did a print(full_url) right after the
> >>> Request
> >>> I tried
> >>> request_object = urllib2.Request('http://www.example.com')
> >>> print(request_object)
> >>> but when printing I get:
> >> Hi João,
>
> >> That's exactly what you want, an object that is an instance of the
> >> Request class. That object doesn't do anything by itself, you still need
> >> to a) Connect to the server and request that URL and b) Read the data
> >> from the server.
>
> >> a) To connect to the web server and initialize the request you need to
> >> call urllib2.urlopen() with the Request object you just created and
> >> assign the result to a name e.g.
>
> response = urllib2.urlopen(request_object)
> >> That will give you an object (response) that you can call the .read()
> >> method of to get the web page data.
>
> the_page = response.read()
> >> If that doesn't make sense or seem to work for you then please try
> >> reading the following website from top to bottom before taking any
> >> further steps...
>
> >>http://www.voidspace.org.uk/python/articles/urllib2.shtml
>
> >>> I've read about Python 2.4 not playing well with proxies even with no
> >>> proxy activated.
> >>> Any sugestion?
> >> I doubt any language can play well with proxies if there are none so I
> >> doubt it's a factor ;)
>
> >> Good luck,
>
> >> Roger.
>
> > lol.
> > I've expressed myself poorly,
> > I meant I read about some issues when getting the Request + urlopen
> > working when there's a proxy involved (like in my case)
> > even when activating a no_proxy configuration, something like,
>
> > proxy_support = urllib.ProxyHandler({})
> > opener = urllib.build_opener(proxy_support)
> > urllib.install_opener(opener)
>
> > But I don't know how to use it :(
>
> That is how you use it IIRC, this installs the proxy handler into urllib
> and subsequent objects you subclass from urllib will use the custom handler.
>
> From what I can tell, you should be using urllib2 though, not urllib.
>
> Lets take a step back. You had the following line...
>
> request_object = urllib2.Request('http://www.example.com')
>
> ...You printed it and it showed that you had created a Request object
> right. Now what happens when you type...
>
> response = urllib2.urlopen(request_object)
> print response
>
> ?
>
> Roger.
Thanks for the patience Roger.
Your explanation opened my eyes.
I finally got it to work, and it turned out I didn't have to include
any custom proxy handler to avoid our proxy.
It ended on such a small and simple block of code after getting the
pieces together..
#!/usr/bin/env python
import sys
from urllib2 import Request, urlopen
from urllib import urlencode
authentication = "UID=124675&PW=gdberishyb8LcIANtvT89QVQ==&"
url = 'http://10.112.28.221:38080/GwHTTPin/sendtext'
encoded_data = urlencode({'M':sys.argv[2],
'N':sys.argv[1]})
# Was having problem with this one, shouldn't have tried to pass the
authentication as an urlencode parameter because it was breaking the
password string!
sent_data = authentication + encoded_data
full_url = Request(url,sent_data)
response = urlopen(full_url).read()
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
João wrote:
> On Jan 15, 2:38 pm, r0g wrote:
>> João wrote:
>>> On Jan 14, 5:58 pm, r0g wrote:
João wrote:
> On Jan 12, 10:07 pm, r0g wrote:
>> João wrote:
> for the following data,
> authentication = "UID=somestring&"
> message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
> Succ. : 94.47%'
> dest_number = 'XXX'
> url_values = urlencode({'M':message})
> enc_data = authentication + url_values + dest_number
> I'm getting null for
> full_url = Request(url, enc_data, headers)
> and thus,
> response = urlopen(full_url).read()
> returns,
> TypeError:
> )
Are you sure it's returning a null and not just some other unexpected
type?
I think your problem may be that you are passing a urllib2 class to
urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
import urllib2
request_object = urllib2.Request('http://www.example.com')
response = urllib2.urlopen(request_object)
the_page = response.read()
Roger.
>>> Thanks Roger.
>>> I think it's a null because i did a print(full_url) right after the
>>> Request
>>> I tried
>>> request_object = urllib2.Request('http://www.example.com')
>>> print(request_object)
>>> but when printing I get:
>> Hi João,
>>
>> That's exactly what you want, an object that is an instance of the
>> Request class. That object doesn't do anything by itself, you still need
>> to a) Connect to the server and request that URL and b) Read the data
>> from the server.
>>
>> a) To connect to the web server and initialize the request you need to
>> call urllib2.urlopen() with the Request object you just created and
>> assign the result to a name e.g.
>>
response = urllib2.urlopen(request_object)
>> That will give you an object (response) that you can call the .read()
>> method of to get the web page data.
>>
the_page = response.read()
>> If that doesn't make sense or seem to work for you then please try
>> reading the following website from top to bottom before taking any
>> further steps...
>>
>> http://www.voidspace.org.uk/python/articles/urllib2.shtml
>>
>>
>>
>>> I've read about Python 2.4 not playing well with proxies even with no
>>> proxy activated.
>>> Any sugestion?
>> I doubt any language can play well with proxies if there are none so I
>> doubt it's a factor ;)
>>
>> Good luck,
>>
>> Roger.
>
> lol.
> I've expressed myself poorly,
> I meant I read about some issues when getting the Request + urlopen
> working when there's a proxy involved (like in my case)
> even when activating a no_proxy configuration, something like,
>
> proxy_support = urllib.ProxyHandler({})
> opener = urllib.build_opener(proxy_support)
> urllib.install_opener(opener)
>
> But I don't know how to use it :(
That is how you use it IIRC, this installs the proxy handler into urllib
and subsequent objects you subclass from urllib will use the custom handler.
>From what I can tell, you should be using urllib2 though, not urllib.
Lets take a step back. You had the following line...
request_object = urllib2.Request('http://www.example.com')
...You printed it and it showed that you had created a Request object
right. Now what happens when you type...
response = urllib2.urlopen(request_object)
print response
?
Roger.
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
EDIT: About the proxy. That's why I'm using the '-P' in the POST call. /usr/bin/POST -P -- http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
On Jan 15, 2:38 pm, r0g wrote:
> João wrote:
> > On Jan 14, 5:58 pm, r0g wrote:
> >> João wrote:
> >>> On Jan 12, 10:07 pm, r0g wrote:
> João wrote:
> >>> for the following data,
> >>> authentication = "UID=somestring&"
> >>> message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
> >>> Succ. : 94.47%'
> >>> dest_number = 'XXX'
> >>> url_values = urlencode({'M':message})
> >>> enc_data = authentication + url_values + dest_number
> >>> I'm getting null for
> >>> full_url = Request(url, enc_data, headers)
> >>> and thus,
> >>> response = urlopen(full_url).read()
> >>> returns,
> >>> TypeError:
> >>> )
> >> Are you sure it's returning a null and not just some other unexpected
> >> type?
>
> >> I think your problem may be that you are passing a urllib2 class to
> >> urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
>
> >> import urllib2
> >> request_object = urllib2.Request('http://www.example.com')
> >> response = urllib2.urlopen(request_object)
> >> the_page = response.read()
>
> >> Roger.
>
> > Thanks Roger.
> > I think it's a null because i did a print(full_url) right after the
> > Request
> > I tried
> > request_object = urllib2.Request('http://www.example.com')
> > print(request_object)
>
> > but when printing I get:
>
> Hi João,
>
> That's exactly what you want, an object that is an instance of the
> Request class. That object doesn't do anything by itself, you still need
> to a) Connect to the server and request that URL and b) Read the data
> from the server.
>
> a) To connect to the web server and initialize the request you need to
> call urllib2.urlopen() with the Request object you just created and
> assign the result to a name e.g.
>
> >> response = urllib2.urlopen(request_object)
>
> That will give you an object (response) that you can call the .read()
> method of to get the web page data.
>
> >> the_page = response.read()
>
> If that doesn't make sense or seem to work for you then please try
> reading the following website from top to bottom before taking any
> further steps...
>
> http://www.voidspace.org.uk/python/articles/urllib2.shtml
>
>
>
> > I've read about Python 2.4 not playing well with proxies even with no
> > proxy activated.
> > Any sugestion?
>
> I doubt any language can play well with proxies if there are none so I
> doubt it's a factor ;)
>
> Good luck,
>
> Roger.
lol.
I've expressed myself poorly,
I meant I read about some issues when getting the Request + urlopen
working when there's a proxy involved (like in my case)
even when activating a no_proxy configuration, something like,
proxy_support = urllib.ProxyHandler({})
opener = urllib.build_opener(proxy_support)
urllib.install_opener(opener)
But I don't know how to use it :(
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
João wrote:
> On Jan 14, 5:58 pm, r0g wrote:
>> João wrote:
>>> On Jan 12, 10:07 pm, r0g wrote:
João wrote:
>>> for the following data,
>>> authentication = "UID=somestring&"
>>> message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
>>> Succ. : 94.47%'
>>> dest_number = 'XXX'
>>> url_values = urlencode({'M':message})
>>> enc_data = authentication + url_values + dest_number
>>> I'm getting null for
>>> full_url = Request(url, enc_data, headers)
>>> and thus,
>>> response = urlopen(full_url).read()
>>> returns,
>>> TypeError:
>>> )
>> Are you sure it's returning a null and not just some other unexpected
>> type?
>>
>> I think your problem may be that you are passing a urllib2 class to
>> urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
>>
>> import urllib2
>> request_object = urllib2.Request('http://www.example.com')
>> response = urllib2.urlopen(request_object)
>> the_page = response.read()
>>
>> Roger.
>
> Thanks Roger.
> I think it's a null because i did a print(full_url) right after the
> Request
> I tried
> request_object = urllib2.Request('http://www.example.com')
> print(request_object)
>
> but when printing I get:
Hi João,
That's exactly what you want, an object that is an instance of the
Request class. That object doesn't do anything by itself, you still need
to a) Connect to the server and request that URL and b) Read the data
from the server.
a) To connect to the web server and initialize the request you need to
call urllib2.urlopen() with the Request object you just created and
assign the result to a name e.g.
>> response = urllib2.urlopen(request_object)
That will give you an object (response) that you can call the .read()
method of to get the web page data.
>> the_page = response.read()
If that doesn't make sense or seem to work for you then please try
reading the following website from top to bottom before taking any
further steps...
http://www.voidspace.org.uk/python/articles/urllib2.shtml
>
> I've read about Python 2.4 not playing well with proxies even with no
> proxy activated.
> Any sugestion?
I doubt any language can play well with proxies if there are none so I
doubt it's a factor ;)
Good luck,
Roger.
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
On Jan 14, 5:58 pm, r0g wrote:
> João wrote:
> > On Jan 12, 10:07 pm, r0g wrote:
> >> João wrote:
>
> > for the following data,
> > authentication = "UID=somestring&"
> > message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
> > Succ. : 94.47%'
> > dest_number = 'XXX'
>
> > url_values = urlencode({'M':message})
> > enc_data = authentication + url_values + dest_number
>
> > I'm getting null for
> > full_url = Request(url, enc_data, headers)
>
> > and thus,
> > response = urlopen(full_url).read()
> > returns,
> > TypeError:
>
> > )
>
> Are you sure it's returning a null and not just some other unexpected
> type?
>
> I think your problem may be that you are passing a urllib2 class to
> urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
>
> import urllib2
> request_object = urllib2.Request('http://www.example.com')
> response = urllib2.urlopen(request_object)
> the_page = response.read()
>
> Roger.
Thanks Roger.
I think it's a null because i did a print(full_url) right after the
Request
I tried
request_object = urllib2.Request('http://www.example.com')
print(request_object)
but when printing I get:
I've read about Python 2.4 not playing well with proxies even with no
proxy activated.
Any sugestion?
Thanks again
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
João wrote:
> On Jan 12, 10:07 pm, r0g wrote:
>> João wrote:
>
> for the following data,
> authentication = "UID=somestring&"
> message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
> Succ. : 94.47%'
> dest_number = 'XXX'
>
> url_values = urlencode({'M':message})
> enc_data = authentication + url_values + dest_number
>
>
> I'm getting null for
> full_url = Request(url, enc_data, headers)
>
> and thus,
> response = urlopen(full_url).read()
> returns,
> TypeError:
>
> )
Are you sure it's returning a null and not just some other unexpected
type?
I think your problem may be that you are passing a urllib2 class to
urllib(1)'s urlopen. Try using urllib2's urlopen instead e.g.
import urllib2
request_object = urllib2.Request('http://www.example.com')
response = urllib2.urlopen(request_object)
the_page = response.read()
Roger.
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
On Jan 12, 10:07 pm, r0g wrote:
> João wrote:
> > On Jan 12, 8:05 pm, r0g wrote:
> >> João wrote:
> >>> Someone please?
> >> Haven't seen your original post yet mate, usenet can be flaky like that,
> >> might have been a good idea to quote your original post!
>
> >> Roger.
>
> > Thanks Roger.
>
> >> João wrote:
> >>> Someone please?
> >>> Hi.
> >>> I'm trying to figure out how to force URLencoding in my Python 2.4.3
> >>> environment, receiving data as an input argument but I'm really at a loss
> >>> here.
>
> >>> What am I doing wrong?
> > headers = { ’User-Agent’ : user_agent }
>
> Those quotes need to be either " or ' i.e.
>
> headers = { 'User-Agent' : user_agent }
>
> If that doesn't sort it then it would be helpful to see a traceback or,
> if it is not crashing, get a description of how it is failing to do what
> you expect.
>
> Cheers,
>
> Roger.
Weird, I had the correct quotes in my script, maybe I've pasted with
some error.
This is my current script,
(and though I got it working with the subprocess.call I don't know how
to use a pure Python version.
for the following data,
authentication = "UID=somestring&"
message = 'PROBLEM severity High: OperatorX Plat1(locationY) global
Succ. : 94.47%'
dest_number = 'XXX'
url_values = urlencode({'M':message})
enc_data = authentication + url_values + dest_number
I'm getting null for
full_url = Request(url, enc_data, headers)
and thus,
response = urlopen(full_url).read()
returns,
TypeError:
)
#!/usr/bin/env python
import sys
import os
import subprocess
from urllib import urlencode, urlopen
from urllib2 import Request
destination = sys.argv[1]
msg = sys.argv[2]
authentication = "UID=somestring&"
dest_number = "&N=%s" % destination
message = '%s' % msg
url_values = urlencode({'M':message})
enc_data = authentication + url_values + dest_number
url = 'http://10.112.28.221:38080/GwHTTPin/sendtext'
subprocess.call('echo "%s" | /usr/bin/POST -P "%s"' % (enc_data, url),
shell=True)
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
João wrote:
> On Jan 12, 8:05 pm, r0g wrote:
>> João wrote:
>>> Someone please?
>> Haven't seen your original post yet mate, usenet can be flaky like that,
>> might have been a good idea to quote your original post!
>>
>> Roger.
>
> Thanks Roger.
>
>> João wrote:
>>> Someone please?
>>> Hi.
>>> I'm trying to figure out how to force URLencoding in my Python 2.4.3
>>> environment, receiving data as an input argument but I'm really at a loss
>>> here.
>
>>> What am I doing wrong?
> headers = { ’User-Agent’ : user_agent }
Those quotes need to be either " or ' i.e.
headers = { 'User-Agent' : user_agent }
If that doesn't sort it then it would be helpful to see a traceback or,
if it is not crashing, get a description of how it is failing to do what
you expect.
Cheers,
Roger.
--
http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
On Jan 12, 8:05 pm, r0g wrote:
> João wrote:
> > Someone please?
>
> Haven't seen your original post yet mate, usenet can be flaky like that,
> might have been a good idea to quote your original post!
>
> Roger.
Thanks Roger.
> João wrote:
> > Someone please?
> > Hi.
> > I'm trying to figure out how to force URLencoding in my Python 2.4.3
> > environment, receiving data as an input argument but I'm really at a loss
> > here.
> > What am I doing wrong?
#!/usr/bin/env python
import sys
from urllib import urlencode, urlopen
from urllib2 import Request
import urlparse
destination = sys.argv[1]
msg = sys.argv[2] #Will I have problems with this one if the input is
multiline?
# the browser identifies itself using the User-Agent header
# after creating the Request object, it's possible to pass in a
dictionary of headers
user_agent = 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1;
SV1; .NET CLR 1.1.4322)' # force the request to be identified as IE
5.5
headers = { ’User-Agent’ : user_agent }
# force no proxy
authentication = 'UID=22541&PW=gdyb21LQTcIANtvYMT7QVQ==&'
# force Unicode display format
message = u'M=%s&' % msg
dest_number = 'N=%s' % destination
data = authentication + message + dest_number
url = 'http://10.112.28.221:38080/GwHTTPin/sendtext'
print 'Encoded URL:', url
#get full URL adding ? to it, followed by the encoded values
#full_url = url + '?' url_values
#should I force url_values = urllib.urlencode(data) instead?
full_url = urllib2.Request(url, data, headers)
response = urllib2.urlopen(full_url) #.urlopen works transparently
with proxies which do not require authentication
processed = urllib.open(full_url)
--
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Re: force URLencoding script
João wrote: > Someone please? Haven't seen your original post yet mate, usenet can be flaky like that, might have been a good idea to quote your original post! Roger. -- http://mail.python.org/mailman/listinfo/python-list
Re: force URLencoding script
Someone please? -- http://mail.python.org/mailman/listinfo/python-list
force URLencoding script
Hi.
I'm trying to figure out how to force URLencoding in my Python 2.4.3
environment receiving data an input argument but I'm really at a loss
here.
What am I doing wrong?
#!/usr/bin/env python
import sys
from urllib import urlencode, urlopen
from urllib2 import Request
import urlparse
destination = sys.argv[1]
msg = sys.argv[2] #Will I have problems with this one if the input is
multiline?
# the browser identifies itself using the User-Agent header
# after creating the Request object, it's possible to pass in a
dictionary of headers
user_agent = 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1;
SV1; .NET CLR 1.1.4322)' # force the request to be identified as IE
5.5
headers = { ’User-Agent’ : user_agent }
# force no proxy
authentication = 'UID=22541&PW=gdyb21LQTcIANtvYMT7QVQ==&'
# force Unicode display format
message = u'M=%s&' % msg
dest_number = 'N=%s' % destination
data = authentication + message + dest_number
url = 'http://10.112.28.221:38080/GwHTTPin/sendtext'
print 'Encoded URL:', url
#get full URL adding ? to it, followed by the encoded values
#full_url = url + '?' url_values
#should I force url_values = urllib.urlencode(data) instead?
full_url = urllib2.Request(url, data, headers)
response = urllib2.urlopen(full_url) #.urlopen works transparently
with proxies which do not require authentication
processed = urllib.open(full_url)
--
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