Re: Easy way to get a list of tuples.
> >
> > Thanks Thomas yes you are right with append. I have tried it but just
> > can't get it yet as append takes only 1 argument and I wish to give it 3.
> >
> You have not showed us what you tried, but you are probably missing a pair
> of brackets.
>
> C:\Users\User>python
> Python 3.6.0 (v3.6.0:41df79263a11, Dec 23 2016, 08:06:12) [MSC v.1900 64 bit
> (AMD64)] on win32
> Type "help", "copyright", "credits" or "license" for more information.
> >>> x = []
> >>> x.append(('a', 'b', 'c'))
> >>> x.append(('p', 'q', 'r'))
> >>> x
> [('a', 'b', 'c'), ('p', 'q', 'r')]
> >>>
>
> Does this help?
>
> Frank Millman
Oh yes I just had one set of brackets with my append.
Thanks
Frank
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Re: Easy way to get a list of tuples.
On 2017-09-21 12:38, Sayth Renshaw wrote: > Thanks Thomas yes you are right with append. I have tried it but just can't > get it yet as append takes only 1 argument and I wish to give it 3. > > I am really having trouble creating the groups of 3, since I am getting one > consistent stream. I suggest you have a very close look at my example code :-) -- Thomas Jollans -- https://mail.python.org/mailman/listinfo/python-list
Re: Easy way to get a list of tuples.
On 21/09/2017 11:18, Sayth Renshaw wrote:
Hi
I have been toying with json and I particular area where I cannot get the
desired result a list of tuples as my return. The json from the API is way to
long but I don't think it will matter.
.. hitting url
data = r.json()
for item in data["RaceDay"]['Meetings'][0]['Races']:
raceDetails = item['RacingFormGuide']['Event']['Race']
print(raceDetails)
This returns
{'Number': 1, 'NumberDisplay': '01', 'Distance': 1000, 'DistanceDisplay': '1000
METRES', 'Name': 'CLASS 3 HANDICAP', 'NameForm': 'HIGHWAY-C3'}
{'Number': 2, 'NumberDisplay': '02', 'Distance': 1600, 'DistanceDisplay': '1600
METRES', 'Name': 'BM 90 HANDICAP', 'NameForm': 'BM90'}
{'Number': 3, 'NumberDisplay': '03', 'Distance': 1100, 'DistanceDisplay': '1100
METRES', 'Name': 'HERITAGE STAKES', 'NameForm': 'HERITAGE'}
{'Number': 4, 'NumberDisplay': '04', 'Distance': 1400, 'DistanceDisplay': '1400
METRES', 'Name': 'BILL RITCHIE HANDICAP', 'NameForm': 'RITCHIE'}
{'Number': 5, 'NumberDisplay': '05', 'Distance': 1400, 'DistanceDisplay': '1400
METRES', 'Name': 'TEA ROSE STAKES', 'NameForm': 'TEA ROSE'}
{'Number': 6, 'NumberDisplay': '06', 'Distance': 1600, 'DistanceDisplay': '1600
METRES', 'Name': 'GEORGE MAIN STAKES', 'NameForm': 'GEO MAIN'}
{'Number': 7, 'NumberDisplay': '07', 'Distance': 1100, 'DistanceDisplay': '1100
METRES', 'Name': 'THE SHORTS', 'NameForm': 'THE SHORTS'}
{'Number': 8, 'NumberDisplay': '08', 'Distance': 2000, 'DistanceDisplay': '2000
METRES', 'Name': 'KINGTON TOWN STAKES', 'NameForm': 'KING TOWN'}
{'Number': 9, 'NumberDisplay': '09', 'Distance': 1200, 'DistanceDisplay': '1200
METRES', 'Name': 'BM 84 HANDICAP', 'NameForm': 'BM84'}
My goal is to select a few elements and create a list of 3 element tuples
like this
[('CLASS 3 HANDICAP', 1, 1000), ('BM 90 HANDICAP', 2, 1600), ('HERITAGE
STAKES', 3, 1100), ('BILL RITCHIE HANDICAP', 4, 1400), ('TEA ROSE STAKES', 5,
1400), ('GEORGE MAIN STAKES', 6, 1600), ('THE SHORTS', 7, 1100), ('KINGTON TOWN
STAKES', 8, 2000), ('BM 84 HANDICAP', 9, 1200)]
I get close creating a list of elements but each attempt I try to create the
list of tuples fails.
This is my closest code
data = r.json()
raceData = []
for item in data["RaceDay"]['Meetings'][0]['Races']:
raceDetails = item['RacingFormGuide']['Event']['Race']
raceData +=
(raceDetails['Name'],raceDetails['Number'],raceDetails['Distance'])
print(raceDetails)
which returns
['CLASS 3 HANDICAP', 1, 1000, 'BM 90 HANDICAP', 2, 1600, 'HERITAGE STAKES', 3,
1100, 'BILL RITCHIE HANDICAP', 4, 1400, 'TEA ROSE STAKES', 5, 1400, 'GEORGE
MAIN STAKES', 6, 1600, 'THE SHORTS', 7, 1100, 'KINGTON TOWN STAKES', 8, 2000,
'BM 84 HANDICAP', 9, 1200]
How do I get the tuples?
Cheers
Sayth
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After a quick glance and hence completely untested:-
raceData.append((raceDetails['Name'],raceDetails['Number'],raceDetails['Distance']))
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Re: Easy way to get a list of tuples.
"Sayth Renshaw" wrote in message
news:cd4aa5c7-47ee-442b-945e-490b0674e...@googlegroups.com...
Thanks Thomas yes you are right with append. I have tried it but just
can't get it yet as append takes only 1 argument and I wish to give it 3.
You have not showed us what you tried, but you are probably missing a pair
of brackets.
C:\Users\User>python
Python 3.6.0 (v3.6.0:41df79263a11, Dec 23 2016, 08:06:12) [MSC v.1900 64 bit
(AMD64)] on win32
Type "help", "copyright", "credits" or "license" for more information.
x = []
x.append(('a', 'b', 'c'))
x.append(('p', 'q', 'r'))
x
[('a', 'b', 'c'), ('p', 'q', 'r')]
Does this help?
Frank Millman
--
https://mail.python.org/mailman/listinfo/python-list
Re: Easy way to get a list of tuples.
On Thursday, 21 September 2017 20:31:28 UTC+10, Thomas Jollans wrote: > On 2017-09-21 12:18, Sayth Renshaw wrote: > > This is my closest code > > > > data = r.json() > > > > raceData = [] > > > > for item in data["RaceDay"]['Meetings'][0]['Races']: > > raceDetails = item['RacingFormGuide']['Event']['Race'] > > raceData += > > (raceDetails['Name'],raceDetails['Number'],raceDetails['Distance']) > > > > print(raceDetails) > > > > You're close! > > The operator += extends a list with the items of another sequence (or > iterable). What you're looking for is the method .append(), which adds a > single element. > > Observe: > > Python 3.6.0 |Continuum Analytics, Inc.| (default, Dec 23 2016, 12:22:00) > [GCC 4.4.7 20120313 (Red Hat 4.4.7-1)] on linux > Type "help", "copyright", "credits" or "license" for more information. > py> a_list = [] > py> a_list += 1,2,3 > py> a_list > [1, 2, 3] > py> a_list.append(4) > py> a_list > [1, 2, 3, 4] > py> a_list += 4 > Traceback (most recent call last): > File "", line 1, in > TypeError: 'int' object is not iterable > py> a_list.append((5,6,7)) > py> a_list > [1, 2, 3, 4, (5, 6, 7)] > py> > > > -- > Thomas Jollans Thanks Thomas yes you are right with append. I have tried it but just can't get it yet as append takes only 1 argument and I wish to give it 3. I am really having trouble creating the groups of 3, since I am getting one consistent stream. Cheers Sayth -- https://mail.python.org/mailman/listinfo/python-list
Re: Easy way to get a list of tuples.
On 2017-09-21 12:18, Sayth Renshaw wrote: > This is my closest code > > data = r.json() > > raceData = [] > > for item in data["RaceDay"]['Meetings'][0]['Races']: > raceDetails = item['RacingFormGuide']['Event']['Race'] > raceData += > (raceDetails['Name'],raceDetails['Number'],raceDetails['Distance']) > > print(raceDetails) > You're close! The operator += extends a list with the items of another sequence (or iterable). What you're looking for is the method .append(), which adds a single element. Observe: Python 3.6.0 |Continuum Analytics, Inc.| (default, Dec 23 2016, 12:22:00) [GCC 4.4.7 20120313 (Red Hat 4.4.7-1)] on linux Type "help", "copyright", "credits" or "license" for more information. py> a_list = [] py> a_list += 1,2,3 py> a_list [1, 2, 3] py> a_list.append(4) py> a_list [1, 2, 3, 4] py> a_list += 4 Traceback (most recent call last): File "", line 1, in TypeError: 'int' object is not iterable py> a_list.append((5,6,7)) py> a_list [1, 2, 3, 4, (5, 6, 7)] py> -- Thomas Jollans -- https://mail.python.org/mailman/listinfo/python-list
